Question

What values of a and b make the equation true? Screenshots attached, please help!

Answer 1

Answer:

Option C is Correct

Step-by-step explanation:

Given:

$\sqrt{648}= \sqrt{2^a.3^b}$

We need to check the values of a and b such that the given equation remains true

1. a= 3 and b=2

$\sqrt{648}= \sqrt{2^3.3^2}\\25.4 = \sqrt{72}\\25.4 \neq 8.4$

So, Option A is incorrect

2. a=2 and b= 3

$\sqrt{648}= \sqrt{2^2.3^3}\\25.4 = \sqrt{108}\\25.4 \neq 10.3$

So, Option B is incorrect

3. a=3, b=4

$\sqrt{648}= \sqrt{2^3.3^4}\\25.4 = \sqrt{648}\\25.4= 25.4$

So, Option C is correct.

4. a= 4, b=3

$\sqrt{648}= \sqrt{2^4.3^3}\\25.4 = \sqrt{432}\\25.4 \neq 20.7$

So, Option D is incorrect.