Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
The answer is B 10/18 and 3/18
(40 min)/(5 mi) = (time)/(7 mi) . . . . . the rates are the same
(7/5)*(40 min) = time = 56 min
At the same rate, it would take Petra 56 minutes to jog 7 miles.
<span> convert the mixed numbers to improper fractions, multiply all numerators, multiply all denominators, and convert your answer to a mixed number (if greater than 1) in lowest terms</span>
27, 36, and 45.
Here's a good nines trick.
9
18
27
36
45
If you pay attention is just adds a ten and minuses a 1 from each number.
8,7,6,5. And 1,2,3,4.
Hope this helps :)