So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:

Suppose that $p+2\geq 0 \iff p \geq -2$

In this case, the absolute value doesn't do anything: the equation is

$p+2 = 10 \iff p = 10-2 = 8$

We are supposing $p \geq -2$ , so we can accept this solution.

Now, suppose that $p+2 < 0 \iff p < -2$ . Now the sign of the expression is flipped by the absolute value, and the equation becomes

$-p-2 = 10 \iff -p = 12 \iff p = -12$

Again, the solution is coherent with the assumption, so we can accept this value as well.

3 0

3 years ago

Juan buys c children’s tickets at each $8 each. He also buys one adult ticket for $12. Write three equivalent expressions for th

salantis [7]

Let T = total cost

Let 8c = total amount of children tickets

Let 12a = total amount of adult tickets

T = 8c + 12a

7 0

3 years ago

logan had a bank account balance of 287 he then deposit 35 and went on a shopping trip if he spends 78 what is his new balance a

gizmo_the_mogwai [7]

The answer is 244 because you add 35 to 287 then subtract 78 and it equals 244

6 0

3 years ago