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3 years ago

[WILL MARK BRAINLIEST] How are logarithms used in the “real world?”

Mathematics

1 answer:

salantis [7]3 years ago

3 0

Answer:

Logarithms are used to model all sorts of things, especially growth and decay!

Step-by-step explanation:

One super-relevant example of how logs are used is in tracking the progress of the coronavirus. There are graphs up on worldometer that show both the linear number of cases and deaths and the log numbers - why? Because this gives us a better idea of when the curve will really flatten, or when it will reach its carrying capacity.

It's also used in things like radioactive decay, or where the growth rate is not constant.

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Greg’s sister Ava is 4 years older than him. If the sum of Greg’s age and 2 times Ava’s age is 35, How old is Ava?

Fofino [41]

Answer:

Step-by-step explanation:

Create an equation: g+(G+4)(2)=35

Parentheses: g+2(G+4)=35

Distributive property: g+2g+8=35

Combine like terms: 3g+8=35

Subtractive property: 3g=27

Division property: g=9

Greg is 9. Since Ava is 4 years older you add 4 to find her age. Ava is 13. You take Ava’s age times 2 ( equals 26) then add Greg’s age (equals 35). And it should equal 35.

3 0

2 years ago

INDEPENDENT:

Leni [432]

Answer: your answers are correct. I inserted an image of the answers.

3 0

3 years ago

Technician A says that a cylinder leakage test fills the cylinder with compressed air and the gauge indicates the percentage of

alukav5142 [94]

Answer:

Technician A is correct.

Step-by-step explanation:

Technician A says that a cylinder leakage test fills the cylinder with compressed air, and the gauge indicates the percentage of leakage.

This is correct.

The cylinder leakage test is also called engine leak down test. Here rather than measuring the ability of engine to generate pressure, compressed air is filled in the cylinder via spark plug hole.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

Find the value of the following expression:

AleksandrR [38]

Answer:

why such complicated questions.....?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers