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3 years ago

[WILL MARK BRAINLIEST] How are logarithms used in the “real world?”

Mathematics

1 answer:

salantis [7]3 years ago

3 0

Answer:

Logarithms are used to model all sorts of things, especially growth and decay!

Step-by-step explanation:

One super-relevant example of how logs are used is in tracking the progress of the coronavirus. There are graphs up on worldometer that show both the linear number of cases and deaths and the log numbers - why? Because this gives us a better idea of when the curve will really flatten, or when it will reach its carrying capacity.

It's also used in things like radioactive decay, or where the growth rate is not constant.

You might be interested in

F(4) = ______<br> If g(x) = 2, x = _____

disa [49]

Answer:

Step-by-step explanation:

From the graph attached,

For x = 4,

Value of the function will be,

f(4) = y value at x = 4

f(4) = -10

Similarly, for y = g(x) = 2,

x value of the function will be,

x = 0

For which g(0) = 2

Therefore, for x = 0 value of the function will be 2.

g(0) = 2

5 0

3 years ago

Can anyone fill these out?

Tcecarenko [31]

Answer:

Part (a)

Part (b)

Find the filled table in the attachment

Part (c)

1/36

Step-by-step explanation:

The total number of possible outcomes using the multiplicative rule is given by;

6*6 = 36.

There are 6 possible outcomes in rolling each die, we simply find the product.

The probability of rolling double sixes is given by;

pr(6 and 6) = pr(6) * pr(6) = 1/6 * 1/6 = 1/36

The probability of rolling double sixes represents independent events and thus we employ the multiplicative rule of probability.

8 0

3 years ago

What is the radius of a circle with an area of 50.24 cubic inches?<br><br> Use 3.14 for pi.

OverLord2011 [107]

Hope this helps you..!!!

3 0

3 years ago

The motorcycle engine on a kawasaki ninja 1000 has a displacement of 1043 cubic-centimeters (cm3). in order to calculate its eng

marishachu [46]

$\boxed{\boxed{ \ 0.061 \frac{inch^3}{cm^3}\ }}$

<h3>Further explanation</h3>

We will calculate the unit conversion factor used to convert its engine displacement from cubic-centimeters to cubic-inches.

The relationships between inch and cm are as follows:

$\boxed{ \ 1 \ inch = 2.54 \ cm\ }$

Inches and cm represent units of length.

Made into fractions, 1 inch as the denominator and 2.54 cm as the numerator.

$\boxed{ \ \frac{1 \ inch}{2.54 \ cm} \ }$

As a unit conversion factor of volume, the numerator and the denominator in cubic.

$\boxed{ \ \frac{(1 \ inch)^3}{(2.54 \ cm)^3} \ }$

$\boxed{ \ \frac{1 \ inch^3}{16.387 \ cm^3} \ }$

Thus, we get the unit conversion factor

$\boxed{\boxed{ \ 0.061 \frac{inch^3}{cm^3}\ }}$

Let's use this unit conversion factor to calculate its engine displacement in new units.

$\boxed{= 1,043 \ cm^3 \times 0.061 \ \frac{inch^3}{cm^3}}$

Note for cm³ units that have been crossed out.

The conversion result is $\ \boxed{ \ 63.623 \ inch^3\ }$

<h3>Learn more</h3>

Convert cubic-kilometers to cubic-meters brainly.com/question/1446243
How to write in scientific notation brainly.com/question/7263463
Calculating mass based on density and volume brainly.com/question/4053884

Keywords: the motorcycle engine, Kawasaki Ninja 1000, 1043 cubic-centimeters (cm³), to calculate, its engine displacement, in cubic-inches (in³), what unit conversion factor

5 0

3 years ago

Read 2 more answers

PLS HELP! GIVING BRAINLIST!

svlad2 [7]

Answer:

We conclude that (4, 2) is NOT a solution to the system of equations.

Step-by-step explanation:

Given the system of equations

$y = x - 2$

$y = 3x + 4$

Important Tip:

In order to determine whether (4, 2) is a solution to the system of equations or not, we need to solve the system of equations.

Let us solve the system of equations using the elimination method.

$\begin{bmatrix}y=x-2\\ y=3x+4\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}y-x=-2\\ y-3x=4\end{bmatrix}$

Subtract the equations

$y-3x=4$

$-$

$\underline{y-x=-2}$

$-2x=6$

Now, solve -2x = 6 for x

$-2x=6$

Divide both sides by -2

$\frac{-2x}{-2}=\frac{6}{-2}$

Simplify

$x=-3$

For y - x = -2 plug in x = -3

$y-\left(-3\right)=-2$

$y+3=-2$

Subtract 3 from both sides

$y+3-3=-2-3$

Simplify

$y=-5$

The solution to the system of equations is:

(x, y) = (-3, -5)

Checking the graph

From the graph, it is also clear that (4, 2) is NOT a solution to the system of equations because (-3, -5) is the only solution as we have found earlier.

Therefore, we conclude that (4, 2) is NOT a solution to the system of equations.

8 0

3 years ago