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Ganezh [65]
3 years ago
11

Which are perfect squares check all that apply 72 36 8 16 81 64 48​

Mathematics
2 answers:
Julli [10]3 years ago
4 0

Answer:36 16

Step-by-step explanation:

Ahat [919]3 years ago
4 0

Answer:

36, 16, 81, and 64.

Step-by-step explanation:

These numbers are perfect squares in that when you find the square root of that number it is a whole number. For example \sqrt{36} = 6 because 6 × 6 =36.

72 is not a perfect square because \sqrt{72} = 8.48528137424, which isn't a whole number.

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How do you find the value of c that satisfy the equation:
victus00 [196]

Answer:

The value of c = -0.5∈ (-1,0)

Step-by-step explanation:

<u>Step(i)</u>:-

Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]

<u> Mean Value theorem</u>

Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

f^{l} (c)  = \frac{f(b) -f(a)}{b-a}

<u>Step(ii):</u>-

Given  f(x) = 4x² +4x -3 …(i)

Differentiating equation (i) with respective to 'x'

          f¹(x) = 4(2x) +4(1) = 8x+4

<u>Step(iii)</u>:-

By using mean value theorem

f^{l} (c)  = \frac{f(0) -f(-1)}{0-(-1)}

8c+4 = \frac{-3-(4(-1)^2+4(-1)-3)}{0-(-1)}

8c+4 = -3-(-3)

8c+4 = 0

8c = -4

c = \frac{-4}{8} = \frac{-1}{2} = -0.5

c ∈ (-1,0)

<u>Conclusion</u>:-

The value of c = -0.5∈ (-1,0)

         

<u></u>

8 0
3 years ago
HELP PLS I WILL MARK BRAINLIEST, DUE TODAYY 100 POINTS!!!!!!!!!
Flauer [41]

Answer:

Y1 intercept = 2

(0,2) (3,-7)

m= (-7 - 2) / (3-0) =-9/3 = - 3

Then y = - 3x + 2

Y2 intercept = - 8

(0,-8) (3,-7)

m = (-7 - - 8) / (3-0) = 1/3

Then y= (1/3)x-8

5 0
3 years ago
Solve. x^2+ 5x-2=0<br> A. <br> B.<br> C.<br> D.
11Alexandr11 [23.1K]

the answer is........ B

4 0
3 years ago
What is another fraction for 2/6?
Whitepunk [10]

Answer:

1/3

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
What is the x of 2/3x squared minus 6x plus 15
iogann1982 [59]
(2/3)x^2 -6x + 15 = 0
Using the quadratic formula:
x = [-b +-sq root(b^2 - 4 *a*c)] / 2a
x= [--6 +-sq root(36 -4*(2/3)*15] / 2*(2/3)
x= [6 +-sq root 36 -40] / (4/3)

x1 = 4.5 + (2i / (4/3))
x1 = 4.5 + 1.5i
x2 = 4.5 - (2i / (4/3))
x2 = 4.5 - 1.5i




4 0
4 years ago
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