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Ganezh [65]
3 years ago
11

Which are perfect squares check all that apply 72 36 8 16 81 64 48​

Mathematics
2 answers:
Julli [10]3 years ago
4 0

Answer:36 16

Step-by-step explanation:

Ahat [919]3 years ago
4 0

Answer:

36, 16, 81, and 64.

Step-by-step explanation:

These numbers are perfect squares in that when you find the square root of that number it is a whole number. For example \sqrt{36} = 6 because 6 × 6 =36.

72 is not a perfect square because \sqrt{72} = 8.48528137424, which isn't a whole number.

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What is the intermediate step in the form (x+a)^2=b(x+a)
Step2247 [10]

Answer:

The intermediate step are;

1) Separate the constants from the terms in x² and x

2) Divide the equation by the coefficient of x²

3) Add the constants that makes the expression in x² and x a perfect square and factorize the expression

Step-by-step explanation:

The function given in the question is 6·x² + 48·x + 207 = 15

The intermediate steps in the to express the given function in the form (x + a)² = b are found as follows;

6·x² + 48·x + 207 = 15

We get

1) Subtract 207 from both sides gives 6·x² + 48·x = 15 - 207 = -192

6·x² + 48·x = -192

2) Dividing by 6 x² + 8·x = -32

3) Add the constant that completes the square to both sides

x² + 8·x + 16 = -32 +16 = -16

x² + 8·x + 16 = -16

4) Factorize (x + 4)² = -16

5) Compare (x + 4)² = -16 which is in the form (x + a)² = b

7 0
3 years ago
Sodium is a reactive metal. chlorine is a reactive gas. these two elements combine to form a
11Alexandr11 [23.1K]
A and d seem correct to me.

b and c are definitely wrong.


8 0
3 years ago
Can someone help me?
tekilochka [14]
Check the picture below.

make sure your calculator is in Degree mode.

5 0
3 years ago
An observation deck extends 120 feet out above a valley. The deck sits 70 feet above the valley floor. If an object is dropped f
Rzqust [24]

Answer:

2

Step-by-step explanation:

The height formula given is:

h = -16t^2 + 70

That means the object will be initially (t=0) at the height 70 feet, from where it will be dropped.

If we want to know the time when the object will be at height 6 feet, we just need to use h=6 in the equation, and then calculate the value of t:

6 = -16t^2 + 70

16t^2 = 64

t^2 =4

t = 2 s

So, it will take 2 seconds for the object to be 6 feet above the valley floor.

8 0
3 years ago
Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 6, \sigma = 0.2

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 5.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

Z = -5

Z = -5 has a pvalue of 0.

1 - 0 = 1

5 0
3 years ago
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