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Semmy [17]
3 years ago
5

Factor and find god p² - 14p

Mathematics
1 answer:
Ber [7]3 years ago
6 0
The common factor is p. so take it out, and you’re left with
p ( p-14 )
You might be interested in
Write an equation for the translation of x^2 + y^2 = 49 by 7 units right and 4 units up
Tatiana [17]

Answer:

(x - 7)² + (y - 4)² = 49

Step-by-step explanation:

Given

Equation: x² + y² = 49

Required:

New Equation when translated 7 units right and 4 units up

Taking it one step at a time.

When the equation is translated 7 units right, this implies a negative unit along the x axis.

The equation becomes

(x - 7)² + y² = 49

When the equation is translated 4 units up, this implies a negative unit along the y axis.

(x - 7)² + (y - 4)² = 49

The expression can be further simplified but it's best left in the form of

(x - 7)² + (y - 4)² = 49

8 0
3 years ago
4. Landon is cooking soup. He has 15 pinan of vegetable broth, 19 pints of milk, and 14 pints of tomato juice. How many gallons
ratelena [41]

Answer:

6 gallons

Step-by-step explanation:

1) add 15 and 19 to get 34

2) then add 34 and 14 to get 48

3) then divide 48 by 8 to get 6

7 0
3 years ago
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
What is the solution to the following system of equations?
kipiarov [429]

Answer:

(0, -6)

Step-by-step explanation:

Given the following systems of linear equations;

3x - 2y = 12 ...... equation 1

16x - 4y = 24 ........ equation 2

We would solve for the solution using the elimination method;

Multiplying eqn 1 by 2, we have;

2 * (3x - 2y = 12)

6x - 4y = 24

16x - 4y = 24

Subtracting the two equations, we have;

(6x - 16x) + (-4y -[-4y]) = (24 - 24)

-10x - 0 = 0

-10x = 0

x = -0/10 = 0

Next, we would find the value of y;

3x - 2y = 12

3(0) - 2y = 12

0 - 2y = 12

-2y = 12

y = -12/2

y = -6

Check:

3x - 2y = 12

3(0) - 2(-6) = 12

0 - (-12) = 12

12 = 12

Note: the options provided for this questions are incorrect or inappropriate.

5 0
3 years ago
Which two of the following is continuous data?
Alla [95]

Answer:

B. Age of student

D. Time taken to run 1 mile

Step-by-step explanation:

From the list of given options, only B and D satisfy the required condition.

One unique determinant of continuous data is that; they are measured and not counted.

Now, let's categorize option A to D into two

1. Counted data

2. Measured data

Options that fall into the category of measured data are said to be continuous data.

A. Concert attendance; The number of people in a concert is counted

B. The age of a student is measured (in years)

C. Number of pens in a box is counted

D. Time taken to run 1 mile is measured (in units like seconds, minutes, hours, etc...)

In summary; we have

Counted

A. Concert Attendance

C. Number of pens in a box

Measured

B. Age of a student

D. Time taken to run 1 mile

Hence, the continuous data are Age of a student and Time taken to run 1 mile

7 0
3 years ago
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