<span>reflection over the x-axis and a translation 4 units down
Refelcting f(x) over the x axis gives
-f(x)=-3x-1
Subtracting a constant from -f(x) moves the graph of -f(x) that many units down.
-f(x)-4=-3x-5=g(x)
This shows that g(x) is obtained by reflecting f(x) over the x-axis and then translating 4 units down.</span>
Answer:
B
Step-by-step explanation:
The figure is a trapezium with area (A) calculated as
A =
h (a + b)
where h is the perpendicular height and a, b the parallel bases
Here h = 8, a = 10 and b = 6, thus
A =
× 8 × (10 + 6) = 4 × 16 = 64 cm² → B
The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.
Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.
By the fundamental theorem of calculus,

The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so


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