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2 years ago

0.5 (2x + 2) = -4 Solve for x.

2 answers:

8 0

Your math problem:0.5(2x+2)=-4

Simplify both sides of the equation:
0.5(2x+2)=-4
Distribute: (0.5) (2x) + (0.5) (2) = -4
You will get x + 1 = -4 (subtract from both sides.)
x=-5
0.5(2*-5+2)=4 <- that was the check
So now you know you’re correct!!
So that’s you’re final answer
x= -5
Hope I helped!!

Ivanshal [37]2 years ago

3 0

0.5(2x+2)=-4

Multiply by 2 on both sides

2x+2=-8

Subtract 2 on both sides

2x=-10

Divide by 2 on both sides

x=-5

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Someone pls help me ASAP! Express the following as the sum of its partial fraction: 2x+4/x(x+2)(x-4)

DaniilM [7]

Answer:

Step-by-step explanation:

$\frac{2x+4}{x(x+2)(x-4)} =\frac{a}{x} +\frac{b}{x+2} +\frac{c}{x-4} \\2x+4=a(x+2)(x-4) +bx(x-4)+cx(x+2)\\$

put x=0

0+4=a(0+2)(0-4)+0+0

-8a=4

a=-4/8=-1/2

put x+2=0 or x=-2

2(-2)+4=0+b(-2)(-2-4)+0

12b=0

b=0

put x-4=0 or x=4

2(4)+4=0+0+c(4)(4+2)

24c=12

c=12/24=1/2

$\frac{2x+4}{x(x+2)(x-4)} =\frac{-1}{2x} +0+\frac{1}{2(x-4)} \\\frac{2x+4}{x(x+2)(x-4)} =\frac{-1}{2x} +\frac{1}{2(x-4)}$

8 0

1 year ago

An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in Texas. He believes that

Llana [10]

Answer:

We need a sample size of at least 170.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.8}{2} = 0.1$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.1 = 0.9$ , so $z = 1.28$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population(square root of the variance) and n is the size of the sample.

How large of a sample would be required in order to estimate the mean per capita income at the 80%80% level of confidence with an error of at most $0.52$ 0.52?

A sample size of at least n, in which n is found when $M = 0.52, \sigma = \sqrt{34.81} = 5.9$

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.58 = 1.28*\frac{5.9}{\sqrt{n}}$

$0.58\sqrt{n} = 1.28*5.9$

$\sqrt{n} = \frac{1.28*5.9}{0.58}$

$(\sqrt{n})^{2} = (\frac{1.28*5.9}{0.58})^{2}$

$n = 169.5$

Rounding up

We need a sample size of at least 170.

6 0

2 years ago

Finding the roots by completing the square

Andrej [43]

For y=x^2-6x-11

complete the square

so roots
set y=0
0=x^2-6x-11

group x terms
0=(x^2-6x)-11
take 1/2 of linear coefient (-6) and square it
-6/2=-3, (-3)^2=9
add positive and neative to inside of parenthasees
0=(x^2-6x+9-9)-11
complete square
0=((x-3)^2-9)-11
expand
0=(x-3)^2-9-11
0=(x-3)^2-20
add 20 to both sides
20=(x-3)^2
sqrt both sides
remember positive and negative roots

+/-2√5=x-3
add 3 to both sides
3+/-2√5=x

so
x=3+2√5 and 3-2√5

6 0

3 years ago

After 8 years, what is the total amount of a compound interest investment of$25,000 at 3% interes compounded quarteriy? A. 525.3

Artyom0805 [142]

I believe its D. Hope it helps you!

8 0

3 years ago

Sam spent the day at the mall. First, he bought three mules for $30

Dmitriy789 [7]

Answer:

180

Step-by-step explanation:

30x3=90-30+50

4 0

2 years ago