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STALIN [3.7K]
3 years ago
11

Eighteen cement squares cover a patio with an area of 40.5m^2. What is the side length of one of the squares

Mathematics
1 answer:
Firlakuza [10]3 years ago
6 0
Idk :)   but the other guy answering might be able to help you. please give me a like!                                
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Kobotan [32]
I would like to say that it was an absolute honor helping you!!
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Put them in order from least to greasiest 3/5 1/4 1/2 2/5
alexira [117]

1/4 < 2/5 < 3/5 < 1/2

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I want to run 4 1/2 miles tonight. If I know running around my block is 3/5 of a mile, how many times should I run around the bl
sukhopar [10]
3/5 block mile is also 0.6 block mile
4 1/2 miles is also 4.5 miles

How many 0.6mi blocks do you run to run 4.5 miles?

4.5miles/0.6block mi = 7.5 or 7 1/2 blocks will equal 4.5 or 4 1/2 miles.

Check 7.5 blocks x 0.6 block mi = 4.5 miles

Same as you know one quarter equals $0.25 cent. And how many do you need to make one dollar that equals $1.00 ?

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3 0
3 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
3 years ago
Please help me for 10 points?
ANEK [815]
Black maybe forty maybe even subtraction
5 0
3 years ago
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