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2 years ago

What is the GCF of g^3 an g^15

Mathematics

1 answer:

kenny6666 [7]2 years ago

8 0

Answer:

The GCF of both is g^3

Step-by-step explanation:

Here, we are asked to give the greatest common factor of g^3 and g^15

In simpler terms we want to find that biggest term that could divide both values.

Mathematically, since g^3 is itself a factor of g^15, then we can conclude that the GCF of both is g^3

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Simplify.<br> -2(x+3)+6x

brilliants [131]

−2(x+3)+6x

Distribute:

=(−2)(x)+(−2)(3)+6x

=−2x+−6+6x

Combine Like Terms:

=−2x+−6+6x

=(−2x+6x)+(−6)

=4x+−6

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2 years ago

1. Devin is making a candle by pouring melted wax into a mold in the shape of a square pyramid. Each side of the base of the pyr

Cloud [144]

Answer:

Devin will need 9 cubes of wax.

Step-by-step explanation:

To find the volume of the pyramid, you use (area of the base)* height of the pyramid divided by 3. You know the volume of a cube of wax is 32 cm^3. The volume of your pyramid is 270 cm^3. 270/32=8.4375.

Once you get 8.4375 cubes, you round to the next whole number, which is nine.

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2 years ago

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Solve<br><br> Please help don’t understand

tigry1 [53]

Answer:x=30*

Step-by-step explanation:

90*+30*=120*

*All triangles’ angles = 180*

180*-120*=60*

60*/2=30*

8 0

2 years ago

I need help finding the angles

Lostsunrise [7]

What way are you trying to solve

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2 years ago

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As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10.

Firdavs [7]

Answer:

New can holds $112.25\,\,cm^3$ more than the old can

Step-by-step explanation:

Given: Diameter of the can is 6 cm and height is 12 cm such that volume of can is $339.12\,\,cm^3$

Dimensions of the can are increased by a multiple of 1.10

To find: Difference between the volume of new can and volume of old can

Solution:

Volume of can (v) = $339.12\,\,cm^3$

Let r, h denote radius and height of the can.

Let R, H denotes radius and height of the new can.

r = diameter/2 = $\frac{6}{2}=3\,\,cm$

h = 12 cm

R = $3(1.1)=3.3.\,\,cm$

H = $12(1.1)=13.2\,\,cm$

New volume (V) = $\pi (R)^2H=\pi(3.3)^2(13.2)=451.37\,\,cm^3$

So,

$V-v=451.37-339.12=112.25\,\,cm^3$

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3 years ago