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kifflom [539]
3 years ago
5

a bag contains 30 lottery balls numbered 1-30. A ball is selected, replaced, then another is drawn. Find each probability

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0
30*29*28*27....etc. Try that
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Need help with this math question
lara [203]

Answer: A. Correlation

Step-by-step explanation: A correlation describes the relationship between two variables, so it would be A

6 0
3 years ago
Use the Polygon tool to draw an image of the given polygon under a dilation with a scale factor of 14 and center of dilation ​(0
puteri [66]

The points are (168, 168) , (168,56) , (112,0) , (70,112)

Given a scale factor is 14 and the center of dilation (0,0)

We need to find the Points using the scale factor and polygon tool

Now to find the new points the equation is

(old points - dilation center)*scale factor + dilation center

As we know the origin is the dilation center which simplifies to

(old point)*dilation center

(12,12) * 14  =  (168,168)

(12,4) * 14 = (168, 56)

(8,0)*14  =   (112, 0)

(5,8) *14  = (70, 112)

Hence the new points are  (168, 168) , (168,56) , (112,0) , (70,112)

Learn more about center of dilation here

brainly.com/question/14101746

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4 0
2 years ago
Helppppp me pleaseeeeee
Crazy boy [7]

Answer:

x-1=0 x=1

x+1=0 x= -1

x+5=0 x= -5

Step-by-step explanation:

3 0
3 years ago
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What is the area of a rectangular prism
Harman [31]

Answer:

A=2

Step-by-step explanation:

6 0
3 years ago
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Afreen says, "I am thinking of 3 consecutive numbers. The first is a multiple of 4, the second is a multiple of 5 and the third
IgorLugansk [536]

Answer:

The 3 ses that we found are:

{4, 5, 6}

{64, 65, 66}

{124, 125, 126}

Step-by-step explanation:

3 consecutive numbers are written as:

n, (n + 1), (n + 2)

We know that the first one is a multiple of 4.

Then n is a multiple of 4:

n = k*4

where k is an integer.

The second one is a multiple of 5, then:

(n + 1) = j*5

where j is an integer.

The last one is a multiple of 6.

(n + 2) = p*6

where p is an integer.

We want to find 3 sets.

The first one is trivial:

n = 4

n + 1 = 5

n + 2 = 6

4 is a multiple of 4

5 is a multiple of 5

6 is a multiple of 6.

Now let's find a set that is not trivial.

First, remember that all the multiples of 5 end with a 0 or a 5,

Then we can look for a value n, that is multiple of 4, and that has a last units digit equal to 4 (then the next one will have a units digit and will be multiple of 5)

For example, 4*6 = 24

24 is a multiple of 4.

The next number is 24 + 1 = 25, which is multiple of 5.

The next number is 25 + 1 = 26, which is not multiple of 6.

So let's try again.

4*11 = 44, is a multiple of 4.

The next number is 44 + 1 = 45

45 is a multiple of 5.

The next number is 45 + 1 = 46, which is not multiple of 6

So we need to try with another set.

4*16 = 64, is a multiple of 4.

The next number is 64 + 1 = 65, which is multiple of 5.

The next number is 66, which is multiple of 6:

6*11 = 66

Then the set:

n = 64

n + 1 = 65

n + 2 = 66

Is a possible set.

Now we can keep trying this, we can see that the next set  has the numbers:

n = 4*31  = 124 is a multiple of 4.

The next number, is 124 + 1 = 125, which is a multiple of 5.

The next number is 125 + 1 = 126, which is multiple of 6

6*21 = 126

Then the set:

n = 124

n + 1 = 125

n + 2 = 126

Is another possible set.

The 3 ses that we found are:

{4, 5, 6}

{64, 65, 66}

{124, 125, 126}

7 0
3 years ago
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