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Hatshy [7]
3 years ago
10

Distance between 4 and -24 on a number line

Mathematics
1 answer:
professor190 [17]3 years ago
3 0
The answer is -10. It is in the middle.
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What is the curve : y= -2x
arsen [322]

The curve is a linear equation.

<h3>What type of curve is the given equation?</h3>

It is actually a linear equation, meaning that this is a straight line, not a an actual "curve".

To view the "shape" of the curve, you need to graph it.

You could use a program or do it by hand, to do it by hand, you need to evaluate a lot of points of the equation, and then graph them to see the general behavior of the equation.

In this case, I graphed it with a program, and in the image, you can see that this is a linear equation that decreases as the variable increases.

If you want to learn more about linear equations, you can read:

brainly.com/question/4074386

4 0
2 years ago
Read 2 more answers
Which statement is true about numbers to the left of 0 on a number line?
NemiM [27]

Answer:

Numbers to the left of 0 on a number line or anywhere are always negative,

Step-by-step explanation:


8 0
3 years ago
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15 - 9 + 2.65 + 1.35 + 2(1.74)
statuscvo [17]
15 - 9 + 2.65 + 1.35 + 3.48
6 + 2.65 + 1.35 + 3.48
8.65 + 1.35 + 3.48
10 + 3.48
13.48
3 0
3 years ago
Evaluate the expression when m=4<br> m^2-9m-5
enyata [817]

Answer:-25

Step-by-step explanation:

simplify

3 0
3 years ago
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If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
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