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Mathematics

1 answer:

Serjik [45]2 years ago

5 0

Y=40x+100 and the second question is y=1.69x

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What is 36:39 in simplest form? А. 1:3 В. 36:39 С. 12:13 D. 13:12

Naddik [55]

Answer:

36:39

= 36/39 (divide by 3)

= 12/13

= <u>12:13 (option C)</u>

5 0

2 years ago

Read 2 more answers

Angle A and angle B are supplementary angles. If the measure of angle A = (3x - 12) and the measure of angle B = (4x - 25), find

Crank

Answer:

what is x so I can help you.

4 0

2 years ago

How do I find the area

inn [45]

Wasssaa,

Steps:

To find the area of a triangle you multiply the base times the height, in this case the is (19m)
and the height is (11m), after you multipy those numbers you divide by (2)
$(19m \times 11m) \div 2$
$\frac{209 }{2}$

Answer:
$104.5sq \: m$
Hope this helped you
:D

8 0

3 years ago

Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .