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Tom [10]
3 years ago
7

Determine the number of real solutions the equation has.

Mathematics
1 answer:
just olya [345]3 years ago
7 0
Using the quadratic formula, the solutions are x1 = 1.3416 and x2 = -1.3416
So, it has 2 real solutions.

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What is the area, in square millimeters, of a right triangle with a hypotenuse of 68 millimeters and a leg of 60 millimeters?
Paladinen [302]
First, we have to solve the sides of the right triangle by using the Pythagorean theorem: a² + b² = c² where c is the length of the hypotenuse. Then, we can use the legs as length and height of the triangle and find the area by 1/2(base x height).

x² + 60² = 68²
x² + 3600 = 4624
x² = 1024
x = √1024
x = 32 = length of the other side

A = (1/2)(32) (60) = 960 mm²
6 0
3 years ago
If y=2x+10 and X= -2 then what is y
lara [203]
Y=2•(-2)+10
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8 0
3 years ago
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a triangular prism has an equilateral base with each side of the triangle measuring 8.4 centimeters The height of the prism is 1
Andrew [12]

The correct answer is:

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|Huntrw6|

8 0
3 years ago
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Solve the equation: [x-2]=[4+x]<br><br>x=
Whitepunk [10]
X-2 = 4+x
+2      +2
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6 0
3 years ago
F(x) = 2(x+3)2 -7<br><br><br> a= <br><br> h=<br><br> k=
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Answer:

Step-by-step explanation:

In vertex form, the equation is

y = a(x-h)^2 + k

So just read off the values!

6 0
3 years ago
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