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Tom [10]
3 years ago
7

Determine the number of real solutions the equation has.

Mathematics
1 answer:
just olya [345]3 years ago
7 0
Using the quadratic formula, the solutions are x1 = 1.3416 and x2 = -1.3416
So, it has 2 real solutions.

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jolli1 [7]
1/9 or 1/3 hope this helps!
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3 years ago
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3x + 9b + 5ax + 15ab​
Irina-Kira [14]

Answer:

(x + 3b)(3 + 5a)

Step-by-step explanation:

Assuming you require the expression factorised.

Given

3x + 9b + 5ax + 15ab ( factor the first/second and third/fourth terms )

= 3(x + 3b) + 5a(x + 3b) ← factor out (x + 3b) from each term

= (x + 3b)(3 + 5a) ← in factored form

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Reptile [31]
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telo118 [61]

Step-by-step explanation:

=  \frac{1}{2}  +  ( - 5 \frac{9}{10} )

=  \frac{1}{2}  - 5 \frac{9}{10}  \\

=  \frac{1}{2}  -  \frac{5 \times 10 + 9}{10}  \\

=  \frac{1}{2}  -  \frac{59}{10}  \\

=  \frac{1}{2}  \times  \frac{5}{5}  -  \frac{59}{10}  \\

=   \frac{5}{10}   -  \frac{59}{10}  \\

=  \frac{5 - 59}{10}  \\

=  -  \frac{54}{10}  \\

=  -  \frac{27}{5}  \\

6 0
2 years ago
Read 2 more answers
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