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Nataly [62]
3 years ago
14

HI PLS ANSWER ASAP! NO WORK NEEDED!

Mathematics
1 answer:
lana66690 [7]3 years ago
3 0

Answerabccd

Step-by-step explanation:

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I believe The answer is B
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Please help with math question! This question is stressing me out (View Image)
TEA [102]
To find the volume of this one we need to break it down 
now i see half of a cylinder and rectangle:)
but first lets find the volume of the rectangle...
In order to find the Volume of a rectangle we need to use this formula...
Length x width x height 
in this case...
length = 10in
width = 6 in 
height = 8in
lets solve:)
10 x 6 x 8 = 480
or we write it like this 
480in³

now time to find the volume of the half cylinder:)
But first lets remember the volume for a cylinder
Volume = \pi r^{2} h
So lets find our measurements 
\pi = 3.14
r² = 5² or 25
h = 6 
so lets plug in our values just like our formula said:)
3.14 x 25 x 6 
now lets easily solve 
<span>3.14 x 25 x 6 = 471
</span>now since we found an entire cylinder and we only want half of a cylinder lets divide our answer in half
471 ÷ 2 = 235.5
so we write it like this 235.5units³
But we have to add both of our multiples together so lets do that
Volume of rectangle = <span>480in³
</span>volume of half sphere = 235.5units³
480 + 235.5 = 715.5
answer = 715.5units³
I hope this helped and everyone learned something new
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MARK ME BRAINLIEST! :D
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3 years ago
What equality is shown above
Bogdan [553]

Answer: If you see this line solid its > or equal too this > with line underneath

If you see line broken it's only >

Y>_ - 1/4x+2

Step-by-step explanation:

Starts at 2 on y then next pt go down 1 and 4 to the right

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3 years ago
The tap drips 25 drops in I min​
Alex_Xolod [135]

Answer:

60 divided 25

Step-by-step explanation:

8 0
2 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
AURORKA [14]

Answer:

(−0.103371 ; 0.063371) ;

No ;

( -0.0463642, 0.0063642)

Step-by-step explanation:

Shift 1:

Sample size, n1 = 30

Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm

Shift 2:

Sample size, n2 = 25

Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17

Mean difference ; μ1 - μ2

Zcritical at 95% confidence interval = 1.96

Using the relation :

(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)

(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)

Lower boundary :

-0.02 - 0.0833710 = −0.103371

Upper boundary :

-0.02 + 0.0833710 = 0.063371

(−0.103371 ; 0.063371)

B.)

We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.

C.)

For sample size :

n1 = 300 ; n2 = 250

(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)

Lower boundary :

-0.02 - 0.0263642 = −0.0463642

Upper boundary :

-0.02 + 0.0263642 = 0.0063642

( -0.0463642, 0.0063642)

7 0
3 years ago
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