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3 years ago

I NEED HELP SO BADLY!!!!!!!!!! WHAT IS THE PERIMETER????? IF CORRECT, I WILL GIVE U BRAINLIEST

Mathematics

2 answers:

nevsk [136]3 years ago

8 0

Answer: 34

Step-by-step explanation: B=10 S1=12 S2=12. Add them up

babunello [35]3 years ago

8 0

Answer:

I'm assuming the sides are 12 and the bottom 10 so your perimeter is 34

If you count the boxes the line of the triangle takes up, its 12 and the bottom is 10

Sides: 12

bottom: 10

If you add them up:

12 + 12 + 10 = 34

You might be interested in

Among all pairs of numbers with a sum of 215, find the pair whose product is maximum. Write your answers as fractions reduced to

valentina_108 [34]

Answer:

Step-by-step explanation:

This is calculus, but I don't get fractions in the end. To maximize or minimize any function, you need to find the derivative of it, set it equal to 0, then solve for the critical values.

Our given equation is

x + y = 215 and we want to maximize the product, xy. Therefore,

y = 215 - x so its product in terms of x is

x(215-x) which is

$215x -x^2$ . The derivative of this is

215 - 2x. Set it equal to 0 to maximize it.

215 - 2x = 0 so

-2x = -215 and

x = 107.5.

Sub this in to solve for y:

y + 107.5 = 215 and

y = 107.5

The product is 11556.25, not that you need it.

6 0

3 years ago

Don’t answer unless you’re 100% sure<br> Also, explain how you also got the answer.

mojhsa [17]

Answer:

a ( copper and nickel

b ( 1034.9

Step-by-step explanation:

Add all the values of melting points

2,651 + -37.89 = 2613.11

2613 + -458 = 2155.11

2155.11 + 1984.32 = 4139.43

Divide the number by the number of numbers: 4139.43/4 = 1034.8575

1034.8575 rounded to the nearest tenth is 1034.9, thats how you find the mean, or the average.

6 0

3 years ago

What is 0.482 repeating as a simplified fraction?

weeeeeb [17]

the idea being, we multiply the value by some power of 10 just to move the repeating digits to the left of the decimal point. We have 3 digits, we'll use 1000, anyhow, without further adieu,

$\bf \begin{array}{|ccl|ll}
\cline{1-3}
\stackrel{\qquad}{x=0.\overline{482}}&&\\
\cline{1-3}
&&\\
\stackrel{\textit{3 digits, we use 3 zeros}}{1000\cdot x}&=&482.\overline{482}\\
&&482+0.\overline{482}\\
&&482+x\\
&&\\
\cline{1-3}
\end{array}\implies 1000x=482+x
\\\\\\
999x=482\implies x=\cfrac{482}{999}$