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3 years ago

Can someone please help me answer this?

Mathematics

1 answer:

posledela3 years ago

8 0

It’s height x width 0.45 X 11= 4.95
Make sure not to put the unit behind it ;)

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Is 4/67 grater that 5/777

Anni [7]

Yes because if you divide 4 by 67 you get about 0.0597 and if you divide 5 by 777 then you get about 0.0064 and 0.0597 is greater than 0.0064

6 0

3 years ago

Write 169=13^2 in logarithmic form

e-lub [12.9K]

Answer:

$\log_{13}(169)=2$

Step-by-step explanation:

The given exponential form is:

$169=13^2$

The base of the given expression on the right is 13 and the exponent is 2.

The number is 169.

In terms of logarithms, the base still remains the base and the exponent becomes the result of the logarithm of the number 169 to the given base 13.

$\log_{13}(169)=2$

4 0

3 years ago

5x-6=10-3x solve for x

hodyreva [135]

Answer:

x = 2

Step-by-step explanation:

Start by combining like terms.

Collecting x terms onto the left side results in 8x;

collecting constants onto the right side results in 16.

Therefore, 8x = 16, and x = 2

4 0

4 years ago

Read 2 more answers

6) Evaluate for x = 3:<br> 3•4x/2

Nikolay [14]

Answer:

Step-by-step explanation:

3×4(x)/2

Plug in 3 to x

3×4(3)/2

3×12/2

36/2

5 0

3 years ago

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

3 years ago