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Alexandra [31]
4 years ago
7

What is the derivative of x to the minus 5 power

Mathematics
2 answers:
Leni [432]4 years ago
7 0
(x^{-5})'=-5x^{-6}
Rudiy274 years ago
3 0
Using implicit differentiation:

y={ x }^{ -5 }\\ \\ y=\frac { 1 }{ { x }^{ 5 } } \\ \\ { x }^{ 5 }\cdot y=\frac { 1 }{ { x }^{ 5 } } \cdot { x }^{ 5 }

\\ \\ { x }^{ 5 }\cdot y=1\\ \\ { x }^{ 5 }\frac { dy }{ dx } +5{ x }^{ 4 }\cdot y=0

\\ \\ { x }^{ 5 }\frac { dy }{ dx } =-5{ x }^{ 4 }\cdot y\\ \\ { x }^{ 5 }\frac { dy }{ dx } =-5{ x }^{ 4 }\cdot \frac { 1 }{ { x }^{ 5 } }

\\ \\ \frac { 1 }{ { x }^{ 5 } } \cdot { x }^{ 5 }\frac { dy }{ dx } =-5{ x }^{ 4 }\cdot \frac { 1 }{ { x }^{ 5 } } \cdot \frac { 1 }{ { x }^{ 5 } }

\\ \\ \frac { dy }{ dx } =-\frac { 5{ x }^{ 4 } }{ { x }^{ 10 } } \\ \\ =-\frac { 5 }{ { x }^{ 6 } }
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5 0
4 years ago
I really need help on this can someone help me please!!!!
Nikitich [7]
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6 0
3 years ago
Use the laplace transform to solve the given initial-value problem. y' 5y = e4t, y(0) = 2
Basile [38]

The Laplace transform of the given initial-value problem

y' 5y = e^{4t}, y(0) = 2 is  mathematically given as

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

<h3>What is the Laplace transform of the given initial-value problem? y' 5y = e4t, y(0) = 2?</h3>

Generally, the equation for the problem is  mathematically given as

&\text { Sol:- } \quad y^{\prime}+s y=e^{4 t}, y(0)=2 \\\\&\text { Taking Laplace transform of (1) } \\\\&\quad L\left[y^{\prime}+5 y\right]=\left[\left[e^{4 t}\right]\right. \\\\&\Rightarrow \quad L\left[y^{\prime}\right]+5 L[y]=\frac{1}{s-4} \\\\&\Rightarrow \quad s y(s)-y(0)+5 y(s)=\frac{1}{s-4} \\\\&\Rightarrow \quad(s+5) y(s)=\frac{1}{s-4}+2 \\\\&\Rightarrow \quad y(s)=\frac{1}{s+5}\left[\frac{1}{s-4}+2\right]=\frac{2 s-7}{(s+5)(s-4)}\end{aligned}

\begin{aligned}&\text { Let } \frac{2 s-7}{(s+5)(s-4)}=\frac{a_{0}}{s-4}+\frac{a_{1}}{s+5} \\&\Rightarrow 2 s-7=a_{0}(s+s)+a_{1}(s-4)\end{aligned}

put $s=-s \Rightarrow a_{1}=\frac{17}{9}$

\begin{aligned}\text { put } s &=4 \Rightarrow a_{0}=\frac{1}{9} \\\Rightarrow \quad y(s) &=\frac{1}{9(s-4)}+\frac{17}{9(s+s)}\end{aligned}

In conclusion, Taking inverse Laplace tranoform

L^{-1}[y(s)]=\frac{1}{9} L^{-1}\left[\frac{1}{s-4}\right]+\frac{17}{9} L^{-1}\left[\frac{1}{s+5}\right]$ \\\\

y(t)=\frac{1}{9} e^{4 t}+\frac{17}{9} e^{-5 t}

Read more about Laplace tranoform

brainly.com/question/14487937

#SPJ4

6 0
2 years ago
ok, so, if i have one F in math, will i fail 6th grade? for references, i live in the Hillsborough county district (in florida)
olchik [2.2K]

Answer: I do not think that failing one class will effect your entire 6th grade year. Although, this is best discussed with your teachers or parents/guardians.

8 0
3 years ago
Masón has planted 6 rows in the vegetable garden. He continues to work, planting 1 row every 2 hours. Write an equation to repre
Sophie [7]
Y=.5x+6

I believe this is right sorry if it’s not.
5 0
3 years ago
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