Yes bc both 3/6 and 2/4 equal 1/2
Answer:
1. x^2-36
X^2-6^2
(X-6)•(x+6)
3. 16y^2-25
4^2 Y^2-5^2
(4y)^2-5^2
(4y-5)•(4y+5)
5. 9a^2-121
3^2 a^2-11^2
(3a)^2-11^2
(3a-11)•(3a+11)
6. 196-x^2
14^2 -x^2
(14-x)•(14+x)
8. 36c^2-d^2
6^2 c^2 -d^2
(6c)^2-d^2
(6c-d)•(6c+d)
11. 1-4a^2
1^2- 2^2 a^2
1^2-(2a)^2
(1-2a)•(1+2a)
If the planes are parallel to one another then they will never intersect (assuming they are distinct planes as the question states).
Otherwise they will intersect along a single line.
Therefore the answer is NEVER - they can never intersect in a pair of lines.
Y + 3 = 1.2(x - 0)
y + 3 = 1.2x - 0
y = 1.2x - 3
