Ask question

Ask question

All categories

3 years ago

5

Jessie needs to calculate the circumferenceof a circle,but she does not have a calculator.since the formula for the circumferenc

es of a circle is c=

1 answer:

Brilliant_brown [7]3 years ago

8 0

Answer:

c=2πr

Step-by-step explanation:

Multiply 2 by pi and the radius. If you don't have a calculator you could just multiply 2x3.14r instead of all of pu

You might be interested in

1. What is the slope-intercept form and what information does it give you?

Leokris [45]

The slope-intercept form<span> is simply the way of writing the equation of a line so that the </span>slope<span> </span><span>Often, this </span>form<span> is called y = mx + b
</span>form<span>.</span>

4 0

2 years ago

Read 2 more answers

10 POINST!!!<br> What is the area of quadrilateral QRST if QS=18 and RT=24? Show your work.

Allisa [31]

Answer:

area= 1/2 × d1 ×d2

d = diagonal

area= 1/2 ×24×18 =216 unit^2

6 0

2 years ago

What is the discriminant of the polynomial below 9x^2-18x+9?

harkovskaia [24]

(3x-3 )(3x-3 ) is answee

6 0

3 years ago

The following balls are placed in an urn: 6 red, 6 yellow, 6 blue, and 2 green. One ball is randomly drawn from the urn. What is

Aliun [14]

The probability is 8 out of 20 or 40 percent

4 0

2 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

harina [27]

$L(x,y,z,\lambda)=8x+8y+4z+\lambda(4x^2+4y^2+4z^2-36)$

$L_x=8+8\lambda x=0\implies 1+\lambda x=0$
$L_y=8+8\lambda y=0\implies 1+\lambda y=0$
$L_z=4+8\lambda z=0\implies 1+2\lambda z=0$
$L_\lambda=4x^2+4y^2+4z^2-36=0\implies x^2+y^2+z^2=9$

$yL_x=y+\lambda xy=0$
$xL_y=x+\lambda xy=0$
$\implies yL_x-xL_y=y-x=0\implies y=x$

$2zL_x=2z+2\lambda xz=0$
$xL_z=x+2\lambda xz=0$
$\implies 2zL_x-xL_z=2z-x=0\implies x=2z$

$2zL_y=2z+2\lambda yz=0$
$yL_z=y+2\lambda yz=0$
$\implies 2zL_y-yL_z=2z-y=0\implies y=2z$

$x=y=2z\implies x^2+y^2+z^2=9\iff 4z^2+4z^2+z^2=9z^2=9\implies z=\pm1$

$z=\pm1\implies y=x=\pm2$

So we have two critical points, (2, 2, 1) and (-2, -2, -1), which respectively give a max of 36 and a min of -36.

5 0

2 years ago