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3 years ago

5

Jessie needs to calculate the circumferenceof a circle,but she does not have a calculator.since the formula for the circumferenc

es of a circle is c=

1 answer:

Brilliant_brown [7]3 years ago

8 0

Answer:

c=2πr

Step-by-step explanation:

Multiply 2 by pi and the radius. If you don't have a calculator you could just multiply 2x3.14r instead of all of pu

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Reptile [31]

Answer:

a) The number of visits between the patrons who buys the season passes shows higher frequency than those who did not buy season passes, in general. However, the minimum value of 1 visit is present for both cases.

b) The mean visits of the patrons are just PARAMETERS. If you want to test your hypothesis using hypothesis testing, the statistics are the z or t scores comparing the parameters (means).

c) The proportion who would have paid less are those with 2 or fewer visits because they would only just paid $82 instead of $100.

Number of patrons with 2 or fewer visits: 16

Total number of patrons who bought season passes: 30

Proportion who would've paid less = 16/30 = 0.5333

Step-by-step explanation:

I just did it

5 0

3 years ago

Suppose you are working in an insurance company as a statistician. Your manager asked you to check police records of car acciden

pochemuha

Answer:

(a) 95% confidence interval for the percentage of all car accidents that involve teenage drivers is [0.177 , 0.243].

(b) We are 95% confident that the percentage of all car accidents that involve teenage drivers will lie between 17.7% and 24.3%.

(c) We conclude that the the percentage of teenagers has not changed since you join the company.

(d) We conclude that the the percentage of teenagers has changed since you join the company.

Step-by-step explanation:

We are given that your manager asked you to check police records of car accidents and out of 576 accidents you selected randomly, teenagers were at the wheel in 120 of them.

(a) Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ~ N(0,1)

where, $\hat p$ = sample proportion teenage drivers = $\frac{120}{576}$ = 0.21

n = sample of accidents = 576

p = population percentage of all car accidents

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population population, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ]

= [ $0.21-1.96 \times {\sqrt{\frac{0.21(1-0.21)}{576} }}$ , $0.21+1.96 \times {\sqrt{\frac{0.21(1-0.21)}{576} }}$ ]

= [0.177 , 0.243]

Therefore, 95% confidence interval for the percentage of all car accidents that involve teenage drivers is [0.177 , 0.243].

(b) We are 95% confident that the percentage of all car accidents that involve teenage drivers will lie between 17.7% and 24.3%.

(c) We are also provided that before you were hired in the company, the percentage of teenagers who where involved in car accidents was 18%.

The manager wants to see if the percentage of teenagers has changed since you join the company.

<u><em>Let p = percentage of teenagers who where involved in car accidents</em></u>

So, Null Hypothesis, $H_0$ : p = 18% {means that the percentage of teenagers has not changed since you join the company}

Alternate Hypothesis, $H_A$ : p $\neq$ 18% {means that the percentage of teenagers has changed since you join the company}

The test statistics that will be used here is <u>One-sample z proportion statistics</u>;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ~ N(0,1)

where, $\hat p$ = sample proportion teenage drivers = $\frac{120}{576}$ = 0.21

n = sample of accidents = 576

So, <u><em>test statistics</em></u> = $\frac{0.21-0.18}{\sqrt{\frac{0.21(1-0.21)}{576} }}$

= 1.768

The value of the sample test statistics is 1.768.

Now at 0.05 significance level, the z table gives critical value of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the the percentage of teenagers has not changed since you join the company.

(d) Now at 0.1 significance level, the z table gives critical value of -1.6449 and 1.6449 for two-tailed test. Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the the percentage of teenagers has changed since you join the company.

4 0

3 years ago

Find the distance between his house

Hunter-Best [27]

Here we are supposed to find the distance between the two points

Suppose A=(-8,-9), B=(-4,-10)

Now As per the distance formula we know that the distance between two points is given by the formula

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\ \\ D= \sqrt{(-4+8)^2+(-10+9)^2}\\ \\ D=\sqrt{(4)^2+(-1)^2}\\ \\ D=\sqrt{16+1}\\ \\ D=\sqrt{17} \ miles$

4 0

3 years ago

Cual es la utilidad de la representacion a escala de diferentes distancias reales

svp [43]

Answer:

Scales are used to represent real distances and proportions into maps and planes, that way we can have a bigger perspective about something just having in paper.

One direct use of scales are seen in architecture plans, there, the architect uses scales to represent the construction he is designing. Also, the architect can have a more complete point of view about the principial elements on his work.

6 0

3 years ago

I'm giving branliest 2X - 3y = 12 in a standard and point slope form

iogann1982 [59]

In slope intercept form it is y=2/3x-4
In point slope form it is 2/3x-y-4 :)

5 0

3 years ago