Answer:
a) The mean is 0.05 and the standard deviation is 0.0218.
b) v. The sampling distribution of p is not approximately normal because n(1 - p) is less than 10.
Step-by-step explanation:
Central Limit Theorem
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean 
and standard deviation 
.
If 
and 
, the sampling distribution of the sample proportion p will be approximately normal.
Consider the population consisting of all adult Americans age 65 and older who prefer to watch the news, and suppose that for this population the actual proportion who prefer to watch online is 0.05.
This means that 
A random sample of n = 100 people
So 
(a) What are the mean and standard deviation of the sampling distribution of p?
Mean 
Standard deviation 
The mean is 0.05 and the standard deviation is 0.0218.
(b) Is the sampling distribution of p approximately normal for random samples of size n 100? Explain.
As n(1-p) < 10, it is not approximately normal, option v.
To find the simple interest, we multiply 500 × 0.06 × 3 to get that:
The interest is: $90.00
making your answer D$590
Answer:
The square root of 121.
Step-by-step explanation:
The square root of 121 is 11. 11x11=121 which makes the square root of 121, 11. The cube root of 125 is 5. Cube roots are numbers that are multiplied by each other to make a number, 125 is 5x5x5 so the cube root is 5. 11 is a greater number than 5 which makes the square root of 121 greater.
Answer:
a. We are 99% confident that the average age of all golfers that play on the golf course is greater than 21.29
Step-by-step explanation:
x% confidence interval:
A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.
In this question:
99% confidence interval for the average age of golfers that play on the area is (35.683, 43.763), which means that we are 99% confident that the mean age of all golfers who play in the area is a value in this interval, and the best conclusion is given by option A, as the lower bound of the interval is greater than 21.
