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skelet666 [1.2K]
3 years ago
13

For y = 3x - 2x^2 +5x^3 show how to find the value for y, when x = 3. Show your work

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
8 0

y \:  =   \: f(x) \:  =  \: 3x \:  -  \: 2 {x}^{2}  \:  +  \: 5 {x}^{3}
Here, y is a cubic function of x.
When x = 3,
y \:  =  \: f(3) \:  =  \: 3(3) \:  -  \: 2 {(3)}^{2}  \:  +  \: 5 {(3)}^{3}
y \:  =  \: 9 \:  -  \: 18 \:  +  \: 135
y \:  =  \: f(3)  \:  =  \: 126
Hence, when x = 3, y = 126.
liq [111]3 years ago
7 0
Y=3(3)-2(3)^2+5(3)^3
y=9-2(3)^2+5(3)^3
y=9-6^2+5(3)^3
y=9-36+5(3)^3
y=9-36+15^3
y=9-36+3,375
y=-27+3,375
y=3,348




Just do the steps as I showed you. Just go little by little for each thing so that you don't mess up our get super confused.
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