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aniked [119]
3 years ago
5

What is the scale on a map or drawing used for

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

cm scale

Step-by-step explanation:

it may help you to understand

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Find the distance between the two points in simplest radical form. (-5,8) (-8,6)
Tanzania [10]

Answer:

\sqrt{445} cannot be reduced any further, so that's the answer.

Step-by-step explanation:

Use the distance formula:

\sqrt{(x2-x1)^{2} +(y2-y1)^{2}} \\\\\sqrt{(-8-10)^{2}+(6--5)^{2}}\\\\\sqrt{(-18)^{2}+(11)^{2}}\\\\\sqrt{(324)+(121)}\\\\= \sqrt{445}\\

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3 years ago
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Answer:

X and y are supplementary.

Step-by-step explanation:

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How Do You Write 6.050 In Expanded Form?
Alex777 [14]

Answer:

6 + 0.05

Step-by-step explanation:

To write a number in expanded form, you write each value of the digits by themselves. For example, let us say that that the number is 250.96 . To write in expanded form, you are essentially stretching out all the non-zero numbers, and keeping them separate (but in the same value), As in the example, we will write it out as expanded form:

250.96 = 200 + 50 + 0.9 + 0.06

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8 0
3 years ago
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Need to confirm that I did work correctly.
expeople1 [14]
Y-int . . . x=0 . . . y-3 = 3 (0+1) . . . y-3 = 3 . . y=6. . . . . . . X-int .. y=0 .. 0-3=3 (x+1) .. -3=3x+3 ... -6=3x ...x=-2
3 0
4 years ago
An Archaeologist in Turkey discovers a spear head that contains 79% of its original amount of C-14. Find the age of the spear he
agasfer [191]

Answer:

The age of the spear head is of 1938 yers.

Step-by-step explanation:

The amount of carbon 14 after years is given by the following equation:

Q(t) = Q(0)e^{-rt}

In which Q(0) is the initial amount and r is the decay rate.

The half life of carbon 14 is 5700 years.

This means that Q(5700) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-5700r}

e^{-5700r} = 0.5

\ln{e^{-5700r}} = \ln{0.5}

-5700r = \ln{0.5}

5700r = -\ln{0.5}

r = -\frac{\ln{0.5}}{5700}

r = 0.00012160476

So

Q(t) = Q(0)e^{-0.00012160476t}

We have to find:

t for which Q(t) = 0.79Q(0). So

Q(t) = Q(0)e^{-0.00012160476t}

0.79Q(0) = Q(0)e^{-0.00012160476t}

e^{-0.00012160476t} = 0.79

\ln{e^{-0.00012160476t}} = \ln{0.79}

-0.00012160476t = \ln{0.79}

0.00012160476t = -\ln{0.79}

t = \frac{-\ln{0.79}}{0.00012160476}

t = 1938.43

Rounding to the nearest year.

The age of the spear head is of 1938 yers.

8 0
3 years ago
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