7√7
using the ' rule of radicals '
• √a × √b ⇔ √ab
simplifying the radicals
√28 = √(4 × 7 ) = √4 × √7 = 2√7
√63 = √(9 × 7) =√9 × √7 = 3√7
√112 = √(16 × 7 ) = √16 × √7 = 4√7
substituting into the expression
3(2√7) - 5(3√7) + 4(4√7) = 6√7 - 15√7 + 16√7 = 7√7
Answer:
8 quaters 3 nickels
Step-by-step explanation:
Answer:
x = -3 +/- square root(22)
Step-by-step explanation:
x = -b +/- square root(b^2 - 4ac) / 2a
ax^2 + bx + c = 0
these are both the quadratic formula but one is solved for the x and another for 0
a= 1
b= 6
c = -13
x= -6 +/- square root( 6^2 - 4(1)(13)) / 2(1)
x = -6 +/- sqrt( 36 + 52) / 2
x= -6 +/- sqrt (88) / 2
sqrt of 88 = 2 x sqrt (22)
divide 2 on each
x= -3 +/- sqrt (22)
The answer is B) x>3
13x - 4 < 12x - 1
13x > 12x + 3
x > 3
Hello :
<span>x²- y = 3 ...(1)
x - y = -3 ...(2)
by (2) : y = x+3
subqct in (1) : x²-x-3 = 3
x²-x-6 =0
(x+2)(x-3) = 0
x+2 =0 or x-3 =0
x=-2 or x=3
if x = -2 y = -2+3 = 1
if x=3 y =3+3 = 6
two solutions : ( -2, 1) , (3,6)</span>
