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blsea [12.9K]
3 years ago
15

Please help im finding this very difficult

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

First calculate price per gram (J) of both jars.

Large jar: J_L=\dfrac{440\mathrm{g}}{1.54\mathrm{£}}\approx 285.71 \mathrm{\frac{g}{£}}

Small jar: J_S=\dfrac{340\mathrm{g}}{1.26\mathrm{£}}\approx 269.84\mathrm{\frac{g}{£}}

Because J_S < J_L we can conclude J_S has best value.

Hope this helps.

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Determine whether the relation is a function: {(6, 1), (8, –3), (6, 7)}.
ICE Princess25 [194]

Hello there! The answer would be the first one, or No. At least one output results in two inputs.

When dealing with functions: you must remember that x does not repeat. So, lets look at the relation given, {(6, 1), (8, –3), (6, 7)}. You can see that x does repeat, so this is not a function. This eliminates second and fourth option choices. Out of the options A and C, A would be your choice since x is the input value and y is the output value, and there are two input values.

Hope his helps and have a  great day!

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Juliette [100K]

Answer:>

Step-by-step explanation:

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3 years ago
Read 2 more answers
Find an equation of the circle that has center (-1,2) and passes through (5,-4).
kherson [118]
General equation for a circle
(x - a)² + (y - b)² = r²
with (a,b) represents the center, (x,y) represents one of the points lie on the circle, and r represents the radius

Determine r² by substituting the points into the general equation
(x - a)² + (y - b)² = r²
(5 - (-1))² + (-4 - 2)² = r²
(5 + 1)² + (-6)² = r²
6² + 36 = r²
36 + 36 = r²
72 = r²

Determine the equation of the circle
(x - a)² + (y - b)² = r²
(x - (-1))² + (y - 2)² = 72
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8 0
3 years ago
Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
3 years ago
Two girls and two boys went to the festival. The total cost of their tickets was $20. Each child paid the same amount for a tick
sattari [20]

Answer: $5

Step-by-step explanation: 4 children divided by 20 equals 5

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2 years ago
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