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3 years ago

Which values of n degree polynomials must there definitely exist an x-intercept. Please explain all the reasoning

Mathematics

2 answers:

disa [49]3 years ago

7 0

Answer:

There will definitely exist an x-intercept for all n degree polynomials (a·xⁿ + c) that have real roots where n>0 or c = -a

Step-by-step explanation:

The x=intercept of a polynomial is the coordinates of the point on the polynomial where the equation of the polynomial f(x) = 0

Therefore, the coordinates of the x-intercept = (k, 0)

Where x = k is the solution of the f(x) = 0

Hence, there will definitely exist an x-intercept for all n degree polynomials (a·xⁿ + c) that have real roots where n>0 or c = -a.

AveGali [126]3 years ago

5 0

Answer: There must be definitely at most n value of x - intercept

Step-by-step explanation: If a polynomial has a value of n degree, then, there must be definitely at most n value of x - intercept.

For instance, The polynomial has a degree of 8, so there are at most 8 x-intercepts and at most 8–1 = 7 turning points.

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An elevator has a placard stating that the maximum capacity is 1296 lb long dash — 8 passengers. So, 8 adult male passengers ca

Masja [62]

Answer:

There is a 98.26% probability that it is overloaded.

This elevator does not appear to be safe.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of males are normally distributed with a mean of 170 lb, so $\mu = 170$

They have a standard deviation of standard deviation of 29 lb, so $\sigma = 29$ .

We have a sample of 8 adults, so we have to find the standard deviation of the sample to use in the place of $\sigma$ in the Z score formula.

$s = \frac{\sigma}{8} = \frac{29}{8} = 3.625$

Find the probability that it is overloaded because they have a mean weight greater than 162 lb, so $X = 162$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{162 - 170}{3.625}$

$Z = -2.21$

$Z = -2.21$ has a pvalue 0.0174.

So, there is a 1-0.0174 = 0.9826 = 98.26% probability that it is overloaded.

Any probability that is above 95% is considerer unusually high. So, this elevator does not appear to be safe, since there is a 98.26% probability that it is overloaded.

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3 years ago