Which values of n degree polynomials must there definitely exist an x-intercept. Please explain all the reasoning
2 answers:
Answer:
There will definitely exist an x-intercept for all n degree polynomials (a·xⁿ + c) that have real roots where n>0 or c = -a
Step-by-step explanation:
The x=intercept of a polynomial is the coordinates of the point on the polynomial where the equation of the polynomial f(x) = 0
Therefore, the coordinates of the x-intercept = (k, 0)
Where x = k is the solution of the f(x) = 0
Hence, there will definitely exist an x-intercept for all n degree polynomials (a·xⁿ + c) that have real roots where n>0 or c = -a.
Answer: There must be definitely at most n value of x - intercept
Step-by-step explanation: If a polynomial has a value of n degree, then, there must be definitely at most n value of x - intercept.
For instance, The polynomial has a degree of 8, so there are at most 8 x-intercepts and at most 8–1 = 7 turning points.
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The correct answer is 112 centimeters
Hope this helped :)
Answer:
1b
2b
3a
Step-by-step explanation:
To compare units either of them have to change to be the same unit
either change inches to yards, or yards to inches.
1 yard is 36 inches, so
3 yards = 3 × 36 = 108 in
100 in < 108 in
3 yards is greater.
Surface area= 2(6x15)+2(7x15)+2(6x7)
=180+210+84
=474m
Volume=15x6x7
=630m^2
Answer:
if its a 90 degree angle u will say 90 -46 to get m<2
if is a 180 degree angle u will say 180-46 to get m<2
hope this helped :) brainliestn pls
