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AURORKA [14]
3 years ago
12

Colin invests £1200 into his bank account. He receives 3% per year simple interest. How much will Colin have after 4 years? Give

your answer to the nearest penny where appropriate.
Mathematics
1 answer:
PolarNik [594]3 years ago
3 0

Answer:

1350.61

Step-by-step explanation:

f(x)=1200(1.03^x)

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Find the circumference and area of a circle with a diameter of 22 inches. Leave your answers in terms of pi.
Gnesinka [82]
The answer for this will be letter d. C = 22π and A = 121π. This is computed using the formula of C= Dπ which is C = (22)π. On the other hand, the area of this circle is computed by using the formula A = <span>πr^2. This is computed as follows:
A = </span><span>πr^2
A = </span><span>π (22/2)^2
A = </span><span>π (11)^2
</span>A = 121<span>π</span><span>

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3 years ago
A random sample of 41 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $19.55 per car. The p
Rashid [163]

Answer:

19.55\pm2.145

Step-by-step explanation:

We use the equation \bar x\pm z^*\sigma/\sqrt n, where \bar x=19.55, \sigma=6.33, n=41, and z^*=2.17. We obtain z^* from the z-score of a 0.97 confidence level.

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2 years ago
What’s the rate of change of this table?
frez [133]
Answer: It would be y=2x.
5 0
3 years ago
Read 2 more answers
I am a 2nd grader i need to know 120/1234x1234x70x0x90x100x12x13x34
maxonik [38]
Anything multiplied by 0 =0
So what is left is 90x100x12x13x34 which is=47,736,000
7 0
3 years ago
Solve<br><img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D
Nostrana [21]

Answer:

\displaystyle   \begin{cases} \displaystyle  {x} _{1} =  - p \\   \displaystyle x _{2}   =  -  q \end{cases}

Step-by-step explanation:

we would like to solve the following equation for x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}  +  \frac{1}{x}  =  \frac{1}{p  + q + x}

to do so isolate \frac{1}{x} to right hand side and change its sign which yields:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{1}{p  + q + x}  -  \frac{1}{x}

simplify Substraction:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{x - (q + p +  x)}{x(p  + q + x)}

get rid of only x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{  - (q + p )}{x(p  + q + x)}

simplify addition of the left hand side:

\displaystyle  \frac{q + p}{pq}     =  \frac{  - (q + p )}{x(p  + q + x)}

divide both sides by q+p Which yields:

\displaystyle  \frac{1}{pq}     =  \frac{  -1}{x(p  + q + x)}

cross multiplication:

\displaystyle    x(p  + q + x)  =   - pq

distribute:

\displaystyle    xp  + xq +  {x}^{2} =   - pq

isolate -pq to the left hand side and change its sign:

\displaystyle    xp  + xq +  {x}^{2} + pq =  0

rearrange it to standard form:

\displaystyle   {x}^{2} +    xp  + xq  + pq =  0

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

\displaystyle  x( {x}^{} +   p ) + xq  + pq =  0

factor out q:

\displaystyle  x( {x}^{} +   p ) +q (x + p)=  0

group:

\displaystyle  ( {x}^{} +   p ) (x + q)=  0

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

\displaystyle   \begin{cases} \displaystyle  {x}^{} +   p  = 0 \\   \displaystyle x + q=  0 \end{cases}

cancel out p from the first equation and q from the second equation which yields:

\displaystyle   \begin{cases} \displaystyle  {x}^{}   =  - p \\   \displaystyle x  =  -  q \end{cases}

and we are done!

3 0
3 years ago
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