Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
Step-by-step explanation:
⇒ 
⇒ 
⇒ 
I will be able to answer this question, if it wasn't sideways
8 / 200 = 4 / 100 = 0.04 ;
Its 0.5. Which would be in fraction form 5/10 meaning its 5 tenths.
