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1 year ago

Can someone please help me with this square root problem?

Mathematics

1 answer:

noname [10]1 year ago

6 0

Answer:

c = 14.9

Step-by-step explanation:

use the pythagorean thereom:

a² + b² = c²

a² = 11 × 11 = 121

b² = 10 × 10 = 100

c² = 121 + 100 = 221

now find the square root of 221:

√221 = 14.866...

round to the nearest tenth:

the 6 next to the 8 means round up.

so the hypotenuse is 14.9

Read more about rate of change at:

brainly.com/question/8728504

4 0

2 years ago

Find the slope of the line passing through the pairs of points and describe the line as rising, falling, horizontal or vertical.

Anna [14]

Answer:

$a.\ m=2,\ \text{the line is rising}\\\\b.\ m=-\dfrac{5}{4},\ \text{the line is falling}\\\\c.\ m=0,\ \text{the line is horizontal}\\\\d.\ m\ is\ unde fined,\ \text{the line is vertical}$

Step-by-step explanation:

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

m > 0, then a line is rising

m < 0, then a line is falling

m = 0, then a line is horizontal

m is undefined, then a line is vertical

(2, 1) and (4, 5)

$m=\dfrac{5-1}{4-2}=\dfrac{4}{2}=2>0\to\text{rising}$

(-1, 0) and (3, -5)

$m=\dfrac{-5-0}{3-(-1)}=\dfrac{-5}{4}=-\dfrac{5}{4}$

(2, 1) and (-3, 1)

$m=\dfrac{1-1}{-3-2}=\dfrac{0}{-5}=0\to\text{horizontal}$

(-1, 2) and (-1, -5)

$m=\dfrac{-5-2}{-1-(-1))}=\dfrac{-7}{0}\ \text{UNDEFINED}\to\text{vertical}$

7 0

3 years ago

F(3)= 5x^2 - 4x + 9<br> evaluate this quadratic function

Neporo4naja [7]

Answer:

$f(3) = 38$

Step-by-step explanation:

Given the quadratic function

$f\left(x\right)=\:5x^2\:-\:4x\:+\:9$

Evaluating the quadratic function

$f\left(x\right)=\:5x^2\:-\:4x\:+\:9$

substitute x = 3

$f\left(3\right)=\:5\left(3\right)^2\:-\:4\left(4\right)\:+\:9$

$f(3) = 45-16+9$

$f(3) = 38$

Therefore,

$f(3) = 38$

6 0

2 years ago

For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year.

lidiya [134]

Answer: $ 125987.80

Step-by-step explanation:

Given: The value, V(t) of $393,000 worth of assets after t years, that depreciate at 15% per year, is given by the formula

$V (t)=V_o(b)^t$ , here $V_o$ is the initial asset value and b is the multiplicative decay factor.

The exponential decay function is given by ;-

$f(x)=A(b)^x$ , where A is the initial value , x is the times period and b is the multiplicative decay factor.

where b = 1-r, r is the rate of decay.

Since r = 15%=0.15

Therefore, b = 1-0.15=0.85

Now ,for 7 years , the value of assets is given by :-

$V=393000(0.85)^7=125986.795\approx125987.80$

Hence, the assets valued at after 7 years = $ 125987.80

4 0

2 years ago

Read 2 more answers

Consider the given density curve. A curve starts at (0, 0), curves up to maximum point (3, question mark), and then decreases do

stepladder [879]

Answer:

Step-by-step explanation:

because i did it its 5

4 0

2 years ago