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4 years ago

What is the measurement of N?A) 23° B) 45° C) 73° D) 81°

Mathematics

2 answers:

alina1380 [7]4 years ago

5 0

D) 81°

explanation:

90°-9° =81°

barxatty [35]4 years ago

5 0

The answer D) 81 so hope this helped =)

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PLEASE HURRY XX <br><br> Find a equation that matches the graph.

Galina-37 [17]

Answer:

x ≥ 3

Step-by-step explanation:

The closed dot represents ≥ and ≤

The dot is located on the number "3"

The closed dot essentially shows that the solution is nothing more than 3 and up.

Let "x" be the variable we use.

x ≥ 3

Best of Luck!

3 0

4 years ago

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Find the circumference using the diameter of 10m

valentina_108 [34]

Step-by-step explanation:

Given:

$d = 10 \: m \implies \: r \: = 5 \: m \\ circumference \: \: \\ c = 2 \pi \: r \\ = 2 \times 3.14 \times 5 \\ = 10 \times 3.14 \\ = 31.4 \: m \\ \orange{ \boxed{\therefore \: circumference \: = 31.4 \: m}}$

6 0

4 years ago

What is the answer to x-6x+2z=-16

Strike441 [17]

x-6x+2z = -16

-5x + 2z = -16

= 5x - 2z = 16

4 0

3 years ago

Please answer this correctly without making mistakes I want ace expert and genius people to answer this correctly without making

Lana71 [14]

Answer:

(g+6)/5

Step-by-step explanation:

3 0

3 years ago

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You are testing the claim that the proportion of men who own cats is smaller than the proportion of women who own cats. You samp

MariettaO [177]

Answer:

Given:You sample 160 men, and 25% own cats

You sample 120 women, and 20% own cats.

To Find : Find the test statistic, rounded to two decimal places.

Solution:

You sample 160 men, and 25% own cats.

No. of men have cats = $\frac{25}{100} \times 160$

= $40$

So, $n_1=160 , y_1=40$

You sample 120 women, and 20% own cats.

No. of women have cats = $\frac{20}{100} \times 120$

= $24$

So, $n_2=120 , y_2=24$

We will use Comparing Two Proportions

$\widehat{p_1}=\frac{y_1}{n_1}$

$\widehat{p_1}=\frac{40}{160}$

$\widehat{p_1}=0.25$

$\widehat{p_2}=\frac{y_2}{n_2}$

$\widehat{p_2}=\frac{24}{120}$

$\widehat{p_2}=0.2$

Let $p_1$ and $p_2$ be the probabilities of men having cat and women having cat receptively

$H_0:p_1=p_2\\H_a:p_1$

$\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{24+40}{160+120}=0.228$

Formula of test statistic : $\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}$

Substitute the values

test statistic : $\frac{0.25-0.2}{\sqrt{0.228(1-0.228)(\frac{1}{160}+\frac{1}{120})}}$

test statistic : $0.986$

So, test statistic is 0.986

8 0

4 years ago