Greetings from Brasil...
We have to remember 2 details:
→ When X = 0, the function intersects the Y axis
→ When Y = 0, the function intersects the X axis
So
1: X = 0
Y = X + 5
Y = 0 + 5
Y = 5
X = 0 and Y = 5 ⇔ (0; 5)
2: Y = 0
Y = X + 5
0 = X + 5
X = - 5
Y = 0 and X = - 5 ⇔ (- 5; 0)
Then the point at which the graph intersects the X and Y axis will be
(0; 5) and (- 5; 0)
So this is easy counting
so 5x^2-3x-9
we have 5 x^2's
-3 x's
-9
wat do we add to that to get
1 x^2's
-5 x's
+6
so we do each
5x^2+what=1x^2
subtract 5x^2
from both sides
what=-4x^2
first is -4x^2
then we have -3x to -5x
-3x+what=-5x
add 3x to both sides
what=-2x
second is -2x
-9 to 6
-9+ what=6
ad d9
what=15
last is 15
thereffor add -4x^2-2x+15
The equation of the circle is determined that you are in the wrong type and the same name you can say to you get your
Answer:
it may be c but im not usre
Step-by-step explanation:
