Answer:
The common difference (or common ratio) = 0.75
Step-by-step explanation:
i) let the first term be 
= 80
ii) let the second term be 
= . r = 80 × r = 60 ∴ r = 
= 0.75
iii) let the third term be 
= . r = 60 × r = 45 ∴ r = 
= 0.75
iv) let the fourth term be 
= . r = 45 × r = 33.75 ∴ r = 
= 0.75
Therefore we can see that the series of numbers are part of a geometric progression and the first term is 80 and the common ratio = 0.75.
Assessed Value = (Fair Market Value) x (0.40) Where 0.40 is the decimal equivalent of 40%. Tax Rate = $5.24/$100 of assessed value = $0.0524 per dollar of assessed value. Taxes = (Assessed Value) x (Tax Rate) = (Assessed Value) x ($0.0524) Hope this helps!
Given:
Data Set: 60 items
Median: 25
lower quartile or Q1: 21
upper quartile or Q3: 42
IQR = Q3 - Q1 = 42 - 21 = 21
The DISTRIBUTION IS SKEWED TO THE RIGHT.
distance between median and Q1: 25 - 21 = 4
distance between Q3 and median: 42 - 25 = 17
Since the distance between Q3 and median is greater than the distance between the median and Q1, the distribution is skewed to the right.
Step-by-step explanation:
H0 : µ ≤ 26.9
Ha : µ > 26.9
a. since the null hypothesis is rejected, we would accept the alternative hypothesis and come to the conclusion that there is enough evidence that beer and cider consumption are higher than 26.9 in the city.
b. type 1 error happens when we reject a true null hypothesis.
this error error in this question would be that our conclusion that beer and cider consumption is greater than 26.9 is not true. what is true is that it is equal to or less than 26.9.
the consequence is that is h0 is false it would be harder to reject it at a lower level of significance.
c. type ii error happens when the null hypothesis is accepted even though it is false. here, error would be that cider we accepted that cider and beer consumption is less than or equal to 26.9 when it is actually greater than 26.9
the consequence is that it would be harder to accept a true h0 at a high level of significance
