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3 years ago

What is the value of x?

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

7 0

The outside angles of a polygon equal 360 degrees

total of the 3 known angles: 140 + 34 + 56 = 230
so x = 360 - 230
x = 130 degrees

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Jerry makes $300 per month but always runs out of money. He has $85 in fixed expenses and $60 in variable expenses that must be

cupoosta [38]

Answer: 155

Step-by-step explanation:

$300-$85-$60= $155

3 0

3 years ago

Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea

Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) $E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c) $P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d) $P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

$P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}$

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

$E(X)= n\frac{M}{N}$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}$

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

$E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

4 0

4 years ago

If q||r, solve for x

mestny [16]

Answer:

Step-by-step explanation:

Since they are parallel then

(7x - 8) + (11x - 28) = 180

18x - 36 = 180

18x = 216

x = 12

4 0

3 years ago

Alice has taken a job with a starting salary of $17,600 and the annual raise of $850. What will her salary be on the 5th year of

pshichka [43]

Answer:

21,850

Step-by-step explanation:

850 x 5 = 4,250

17,600 + 4250 = 21,850

7 0

3 years ago

Graph this line using the slop and y intercept. y=1/2x +4

trasher [3.6K]

Answer:

Download photomath you can take a picture of the equation and it will show you how it should be graphed.

5 0

3 years ago

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