The volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)
<h3>How to determine the volume?</h3>
The complete question is added as an attachment
From the attached image, we have:
Length = 12 - 2x
Width = 7 - 2x
Height = x
The volume is calculated as:
Volume = Length * Width * Height
Substitute the known values in the above equation
Volume = (12 - 2x) * (7 - 2x) * x
This gives
Volume = x(12 - 2x)(7 - 2x)
Hence, the volume of the box as a polynomial in the variable x is x(12 - 2x)(7 - 2x)
Read more about polynomial at:
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The coordinates of B would be (2, -4)
In order to find this, we need to know that the value of M's points will always be the average of A and B's points. This is because it is the midpoint. Therefore we can use the following formula.
Value of x
(A + B)/2 = M
(-8 + B)/2 = -3
-8 + B = -6
B = 2
Then we can do the same for the y values
Value of y
(A + B)/2 = M
(-2 + B)/2 = -3
-2 + B = -6
B = 4
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
For circumference it’s 12x3.14= 37.68
83 percent.
Simply do 11-6, which is 5; then do 5/6, and multiply by 100 to get the percent. That equals out to be 83.3333 percent. Or 83 percent when rounding.
