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elena-14-01-66 [18.8K]
3 years ago
6

Three litres of milk cost r29,95 at shop a and two liters of milk cost r15,95 at shop

Mathematics
1 answer:
Savatey [412]3 years ago
6 0
At first shop the 3 liters of milk cost 2995
cost per liter = cost / volume
cost per liter = 2995 / 3 L
cost per liter = 998 per liter of milk

at second shop the two liters of milk cost 1595
 cost per liter = cost / volume
cost per liter = 1595 / 2 L
cost per liter = 797.5 per liter of milk
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Alan's dogs have a total of 24 legs (l). If each dog has 4 legs, which equation gives the number of dogs (d) that Alan has?
N76 [4]
Your answer would be A
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3 years ago
E is the midpoint of DF. IF DE = x + 5 and DF = 3x + 2, what is DF?
prisoha [69]

Answer:

13

Step-by-step explanation:

x+5=3x+2

5=2x+2

3=2x

x=1.5

1.5+5=6.5

6.5 is half of DF, DF=13

6 0
3 years ago
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A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = −16t2 + 48t where t equals the
zlopas [31]
1. The function h(t)=-16t^{2}+48t is a parabola of the form ax^{2}+bx. The the formula for the axis of symmetry of a parabola is x= \frac{-b}{2a}. We can infer from our function that a=-16 and b=48, so lets replace those values in our formula:
x= \frac{-b}{2a}
x= \frac{-48}{-2(16)}
x= \frac{-48}{-32}
x= \frac{3}{2}
x=1.5
We can conclude that to the left of the line of symmetry the ball is reaching its maximum height, and to the right of the line of symmetry the ball is falling.

2. Lets check how much time the ball takes to reach its maximum height and return to the ground. To do that we are going to set the height equal to zero:
0=-16t^{2}+48t
-16t(t-3)=0
t=0 or t-3=0
t=0 or t=3
From our previous point we know that the ball reaches its maximum time at t=1.5, which means that <span>it takes 1.5 seconds to reach the maximum height and 1.5 seconds to fall back to the ground.</span>

7 0
3 years ago
Read 2 more answers
\ Which center of a triangle is also the center of gravity of the triangle? orthocenter centroid incenter circumcenter
Citrus2011 [14]
That is the centroid.

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3 0
3 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

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a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
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