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ki77a [65]
3 years ago
7

I will buy a drum set if and only if I save my allowance. Determine the conditions that make the biconditional true. A. It is tr

ue if I buy a drum set and I save my allowance. It is true if I buy a drum set and I don’t save my allowance. B. It is true if I don't buy a drum set and I save my allowance. It is true if I don’t buy a drum set and I don't save my allowance.. C. It is true if I buy a drum set and I don’t save my allowance. It is true if I don’t buy a drum set and I don’t save my allowance. D. It is true if I buy a drum set and I save my allowance. It is true if I don’t buy a drum set and I don’t save my allowance.
Mathematics
1 answer:
MAXImum [283]3 years ago
8 0
D, because you can only buy a drum set if you save your allowance and you cannot buy a drum set if you don't save your allowance
You might be interested in
Two lengths of a triangle are shown.
Solnce55 [7]

Answer:

11 ft

Step-by-step explanation:

Given the two lengths of a triangle as

AB = 6ft

AC = 6ft

This is an isosceles triangle because only 2 sides are equal.

In an isosceles triangle, the sum of 2 (sides) lengths must be greater than the other length.

Therefore, let's assume the following:

i) AC + AB > BC

6 + 6 > BC

12 > BC (BC is less than 12)

BC < 12

ii) BC + AC > AB

BC + 6 > 6

BC > 6 - 6

BC > 0

Therefore the range of values for BC =

0 < BC < 12

Since BC must be bigger than one of the lengths and it must also be less than the sum of the 2 sides. The length of BC could be 11 because it is less than (6+6) 12 and greater than 6.

5 0
3 years ago
An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de
Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have:

P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have

P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453

The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

8 0
3 years ago
I dont get my mom doesn't get this help me pls
Mariana [72]

5. C. Liquid 2 because 3ml = 1g, 6ml = 2g

6 C. Lead because 75.7 divided by 6.7 = 11.3

7. C. Copper because 89 divided by 10 = 8.9

6 0
3 years ago
Read 2 more answers
Find a,b,and c for the answer
Svetach [21]
Alright give me a second ok
3 0
3 years ago
What is the quotient? 40,561 divided by 47
kumpel [21]
40,561÷ 47= 863

Hoped this helped.

~Bob Ross®
6 0
3 years ago
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