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den301095 [7]
3 years ago
11

Solve for the variable: -15r – 8 = 37 A. -5 B. -3 C. -2 D. 3

Mathematics
2 answers:
aksik [14]3 years ago
8 0
Hello!  I would be happy to help you with your math problem.  For this problem, we plug in the values until we find what fits.  In this case, we have to find what is true, or, in other words, equals 37.

The answer to your question would be B -- -3.  Here is why.

-15*-3-8=37.

Hope this helps!
4vir4ik [10]3 years ago
4 0
Answer:  [B]:  -3 .
______________________________________________________
Explanation:
______________________________________________________
Given:
__________________________________________
  "  <span>-15r – 8 = 37 " ;   Solve for " r "  ;
__________________________________________
</span>     →  Add  "8" to each side of the equation ; 
<span>__________________________________________
     </span>→  -15r – 8 + 8 = 37 + 8 ; 
__________________________________________
to get:
__________________________________________
     →  -15r  =  45 ;
__________________________________________
     → Divide EACH side of the equation by "-15" ; to isolate the variable, "r", on one side of the equation; and to solve for, "r" ; 
___________________________________________
     →  -15r / -15  =  45 / -15 ;
___________________________________________
          →   r  =  - 3  ; which is our answer; 
________________________________________
          →   which is:  Answer choice:  [B]:  "-3" .
______________________________________________________
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the horizontal distance between the child and the crackers is 2.9 ft .

<u>Step-by-step explanation:</u>

Here we have , A child spots crackers in a cabinet at an angle of elevation of 50. The crackers are 3.5 ft above the child. We need to find what is the horizontal distance between the child and the crackers . Let's find out:

According to question , we have a right angle triangle with parameters as :

Perpendicular =3.5\\Base = ?\\x = 50 ,  Where x is angle of elevation !

We know that  , Tanx = \frac{Perpendicular}{Base}

⇒  Tanx = \frac{Perpendicular}{Base}

⇒  Tan50 = \frac{3.5}{Base}

⇒  Base = \frac{3.5}{Tan50}

⇒  Base = \frac{3.5}{1.19}

⇒  Base =2.9ft

Therefore , the horizontal distance between the child and the crackers is 2.9 ft .

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scZoUnD [109]

Answer:

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Step-by-step explanation:

hello,

we can write

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hope this helps

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