Answer: 1. 3g+14
2. 29n+21
3. 10p+8
4. 12e-8-3e
5. 9t
7. -22+3b
Step-by-step explanation:
1. 5g-2(g-7)
5g-2g+14
3g+14.
2. 32n-3(n-7)
32n-3n+21
29n+21
3. 12p-2(p-4)
12p-2p+8
10p+8
4. 4(3e-2)-3e
12e-8-3e
5. -5t(t-3)
-6t+15t
9t
7. -4(3-b) +2(3b +2)-7(b+2)
-12+4b+6b+4-7b-14
-22+3b
You need to have a photo. We can't do this bc we don't have a pic
I think it would be 42 because 42/2 = 21/1 which = 21 and then 21+9=30
Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula
where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,
or,
or,
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change =
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.