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GaryK [48]
3 years ago
14

A forward horizontal force of 3 lb is used to pull a 60 lb sled at constant velocity on a frozen pond. the coefficent of (kineti

c) friction is:
1. 0.2
2. 0.05
3. 0.5
4. 20
5. 2
Physics
1 answer:
puteri [66]3 years ago
7 0
It’s either 0.05 or 20. Assuming that the coefficient friction is a damping factor, I feel like 0.05 would be correct m
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The boom of a fire truck raises a fireman (and his equipment – total weight 280 lbf) 60 ft into the air to fight a building fire
Katen [24]

Answer:

a)Work done by fireman=   2.15  Btu

b) Time t= 0.86 sec

Explanation:

Given that

Weight = 280 lbf

We know that 1 lbf = 4.44 N

so 280 lbf = 1245.5 N

Weight =1245.5 N

Height h = 60 ft

We know that

1 ft = 0.3048 m

So 60 ft = 18.28 m

 h =18.28 m

Power = 3.5 hp

We know that

1 hp =0.74 KW

So 3.5 hp = 2.61 KW

Power = 2.61 KJ/s

So the work done by fireman = Weight x h

Now by putting the values

Work done by fireman= 1245.5 x 18.28 J

Work done by fireman=   2267.74 J

Work done by fireman=   2.26774  KJ

We know that 1 Btu= 1.05 KJ

So   2.266 KJ = 2.15 Btu

Work done by fireman=   2.15  Btu

We know that ,rate of work is called power.

Power x time =  work

2.61 x t = 2.26

So t= 0.86 sec

6 0
3 years ago
A circuit with two or more branches for current to flow
Natalija [7]

If there's any point in a circuit where the current has a choice
of which branch to take, then you have a <em>parallel circuit</em>.


4 0
3 years ago
The wavelength of red light is 7 x 10^-7 meter. Express this value in nanometers
3241004551 [841]

  • The wavelength of the red light in "nanometer" is 7× 10^{2}

  • Wavelength is given as : 7×10^{-7} meter

  • 1 nanometer = (10^{-9} meter)

  • Let X= value of the wavelength in nanometer.

1 nanometer  = 10^{-9} meter

X nanometer = 7× 10^{-7}  meter

  • <em>If we Cross multiply</em>

X nanometer = (\frac{     7* 10^{-7} }{  10^{-9} })

X= 7×10^{2} nanometer

Therefore, the wavelength in "nanometer" is 7×10^{2}

Learn more at :brainly.com/question/12924624?referrer=searchResults

6 0
3 years ago
You drag a crate across a floor with a rope. The force applied is 750 N and the angle of the rope is 25.0° above the horizontalH
frez [133]

a.

The work done by a constant force along a rectilinear motion when the force and the displacement vector are not colinear is given by:

W=F\cos\theta\cdot d

where F is the magnitude of the force, theta is the angle between them and d is the distance.

The problen gives the following data:

The magnitude of the force 750 N.

The angle between the force and the displacement which is 25°

The distance, 26 m.

Plugging this in the formula we have:

\begin{gathered} W=\left(750\right)\left(\cos25\right)\left(26\right) \\ W=17673 \end{gathered}

Therefore the work done is 17673 J.

b)

The power is given by:

P=\frac{W}{t}

the problem states that the time it takes is 6 s. Then:

\begin{gathered} P=\frac{17673}{6} \\ P=2945.5 \end{gathered}

Therefore the power is 2945.5 W

5 0
1 year ago
What is the average (mean) of these numbers: 13,43, 12, 3,66​
algol13

Answer:

27.4

Explanation:

(13+43+12+3+66)/5

137/5

27.4

3 0
3 years ago
Read 2 more answers
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