Answer:
The velocity with which the jumper strike the mat in the landing area is 6.26 m/s.
Explanation:
It is given that,
A high jumper jumps over a bar that is 2 m above the mat, h = 2 m
We need to find the velocity with which the jumper strike the mat in the landing area. It is a case of conservation of energy. let v is the velocity. it is given by :

g is acceleration due to gravity

v = 6.26 m/s
So, the velocity with which the jumper strike the mat in the landing area is 6.26 m/s. Hence, this is the required solution.
Answer:
Two times as much
Explanation:
The equation for gravitational force is: Fg = GMm/r^2 with G being the universal gravitational constant.
So to make things easier we'll set r equal to 1 since it's a constant as well as G.
Then we're left with Fg=Mm with M being the mass of the sun and m being the mass of the earth.
So if m is constant and supposedly equals 1 then Fg=M so Fg is proportional to M therefore if M doubles then Fg doubles.
Oxidation number is the charge.
False?
science can be a motivation out of curiosity AND societal needs.
For example:battery operated cars, are a curiosity and beneficial to the earths environment
Because it eats plants and animals.