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Rashid [163]
3 years ago
8

PLEASE HELP ILL MARK YOU BRAINLIEST Given the expression: 6x10 − 96x2 Factor the entire expression completely. Show the steps of

your work.
Mathematics
2 answers:
Alika [10]3 years ago
5 0

Answer:

192 is the answer

Step-by-step explanation:

Because

96

*2

____192

Mandarinka [93]3 years ago
3 0

Answer:

6x¹⁰ - 96x²

6x²(x⁸ - 16)

B) 6x²(x⁸ - 16)

6x²[(x⁴)² - 4²]

6x²[(x⁴ - 4)(x⁴ + 4)]

6x²(x⁴ + 4)[(x²)² - 2²]

6x²(x⁴ + 4)(x² - 2)(x² + 2)

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a student found the slope of a line that passes through the points (1,14) and (3,4) to be 5. what mistake did she make?
mariarad [96]
x_{1}=1
x_{2}= 3
y_{1} =14
y_{2}=4
Slope= \frac{rise}{run} = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} } = \frac{4-14}{3-1} = \frac{-10}{2} =-5


answer: The student flipped the y values
3 0
3 years ago
If f(x)=2x+5, then f(4) represents what
RSB [31]
<span>f(x)=2x+5
then
</span><span>f(4)=2(4) +5 = 8 + 5 = 13

hope it helps</span>
6 0
3 years ago
What does x equal in this equation: 24+3x=3x+3(7-1) Please help this is due tomorrow!
Zinaida [17]

                                              24 + 3x = 3x + 3(7 - 1)

Eliminate the parentheses:    24 + 3x = 3x + 3(6)

                                              24 + 3x = 3x + 18

Subtract  3x  from each side:       <em>24  =  18</em>

Look at that for a second.  Can ANY value of 'x' make 24 equal to 18 ?
I don't think so.
There's NO number that makes the equation a true statement.

That's just another way to say: "The equation has NO solution."


3 0
3 years ago
Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot
Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

\frac{dm}{dt} = -\frac{t}{\tau}

Where:

m - Current mass of the isotope, measured in kilograms.

t - Time, measured in days.

\tau - Time constant, measured in days.

The solution of the differential equation is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}

\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }

The half-life of a isotope (t_{1/2}) as a function of time constant is:

t_{1/2} = \tau \cdot \ln2

t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2

The half-life difference between isotope B and isotope A is:

\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|

If \frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9, t_{A} = 33\,days and t_{B} = 43\,days, the difference in the half-lives of the isotopes is:

\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|

\Delta t_{1/2} \approx 65.788\,days

The approximate difference in the half-lives of the isotopes is 66 days.

4 0
3 years ago
Read 2 more answers
Simplyfy it -25 + 14 ÷ (5 – 3)​
Gnesinka [82]

Step-by-step explanation:

-25 + 14 ÷ (5-3)

= -25 + 14 ÷ (2)

= - 25 + 7

= - 18

6 0
2 years ago
Read 2 more answers
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