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Anit [1.1K]
3 years ago
10

What is the sum of the next two terms in the sequence -3, -1, 3, 9, 17.....?

Mathematics
1 answer:
iVinArrow [24]3 years ago
7 0

First we have to figure out what the next 2 terms are, ya reckon ?

Look at the terms we have:

From the 1st to the 2nd term . . . add <em>2</em>
From the 2nd to the 3rd term. . . add <em>4</em>
From the 3rd to the 4th term . . . add <em>6</em>
From the 4th to the 5th term . . . add <em>8</em>

So there's the pattern we want.

To get the next term,          we add  <em>10</em>  to 17, and get  27.
And for the one after that, we add  <em>12</em>  to 27, and get 39 .

To answer the question, the sum of (27 + 39) is<em>  <u>66</u></em> .


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14.9

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The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out
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Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So p = 0.3723

12 games in November

So n = 12

What is the probability that the hockey team wins 6 games in November?

This is P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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0.1505 = 15.05% probability that the hockey team wins 6 games in November

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3 years ago
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