Answer:
5.55% of broilers weigh between 1143 and 1242 grams
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What proportion of broilers weigh between 1143 and 1242 grams?
This is the pvalue of Z when X = 1242 subtracted by the pvalue of Z when X = 1143.
X = 1242
has a pvalue of 0.0869
X = 1143
has a pvalue of 0.0314
0.0869 - 0.0314 = 0.0555
5.55% of broilers weigh between 1143 and 1242 grams
Answer:
= 3b/4
Step-by-step explanation:
= b . 4/12 + b . 3/12 + b . 2/12
Apply the fraction rule: a/c + b/c = a + b/c
= b . 4 + b . 3 + b . 2/12
= 4b + 3b + 2b/12
Add similar elements: 4b + 3b + 2b = 9b
= 9b/12
Cancel 9b/12: 3b/4
= 3b/4
Answer: The domain is [0, 4] when the graph is negative.
Answer:
supplementary, 65 degrees
Step-by-step explanation: