Y = -4x - 2
P (-16, -11)
a = -4, b = 0, c = -2
m = -a/b
m = -(-4)/(-2)
m = 4/(-2)
m = -2
y-yo = m(x-xo)
y-(-11) = -2[x-(-16)]
y+11 = -2(x+16)
y+11 = -2x-32
2x+y+11+32 = 0
2x+y+43 = 0
A outra questão é semelhante.
1 sixths would be the awnser you just take away four from five that will give you one so you just need to add the sixths part
Answer:
Amplitude: 4
Period: π
midline: y = 1
Step-by-step explanation:
r(x) = -4 sin(2x) + 1
r(x) = a sin(bx + c) + d where |a| is the amplitude and |b| for the period
a = -4 |a| = 4 : Amplitude = <u>4</u>
b = 2 |b| = 2 period of sin(x) = 2π
period of sin(bx + c) = 2π/|b| = 2π/2 = <u>π</u>
range of sin(2x) ... -1 ≤ sin(2x) ≤ 1
range of -4 sin(2x) + 1: -4+1 ≤ -4 sin(2x) + 1 ≤ 4+1
-3 ≤ -4 sin(2x) + 1 ≤ 5
midline: y = (-3 + 5) / 2 = 1 y = 1
Ok so since it's 62 and 3/4 hours in decimal form it would be 62.75 hours. then u multiply this by 60 because 1 hours has 60 minutes and you get 3765 minutes.
