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3 years ago

I need help with this question.

Mathematics

1 answer:

mars1129 [50]3 years ago

7 0

Step-by-step explanation:

area of ∆ ACB = 1/2× AB×CP

= 1/2× 16× 21 m²

=8×21m²

= 168m²

optionC

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Math knock know I need help, please

Mamont248 [21]

Answer:

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= 4 + 2(-7 - (-10))

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= 4 + 2(3)

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3 years ago

Read 2 more answers

How to find matrics M

makkiz [27]

$\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]$

$(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1$

$(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]$

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4 years ago

what about 3/4 of the students in our class take the bus to school what percent of the students in a class take the bus to schoo

labwork [276]

75%
3/4 is equal to 75%.

7 0

3 years ago

The mean score of 15 students was 82.0. (a) Another student joins, and the mean becomes 82.5. What is the new student's score? (

slega [8]

Answer:

a) The new student's score is 90.

b) Their scores are a pair of scores lower than 100 with a mean of 90.5.

Step-by-step explanation:

The mean is the sum of all scores divided by the number of students.

The mean score of 15 students was 82.0

This means that there are 15 students and the sum of the scores is 15*82 = 1230.

(a) Another student joins, and the mean becomes 82.5. What is the new student's score?

Now there are 16 students, the sum of the scores is 1230 + x and the mean is 82.5. So

$82.5 = \frac{1230 + x}{16}$

$1230 + x = 16*82.5$

$x = 1320 - 1230$

$x = 90$

The new student's score is 90.

(b) Suppose instead that two students join, taking the average from 82 to 83. What could their scores be, if they are restricted to be integer (i.e. whole) numbers?

Now there are 2 new students, so 17 in total. The mean score of the new students is 2x. The total score of the class is 1230 + 2x and the mean is 83. So

$83 = \frac{1230 + 2x}{17}$

$1230 + 2x = 1411$

$2x = 181$

$x = 90.5$

The mean of the two students scores is 90.5.

So their scores are a pair of scores lower than 100 with a mean of 90.5.

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3 years ago

Seventy concert tickets were sold for $550. each adult ticket cost $9 and each childrens ticket cost $5. find the number of adul

PilotLPTM [1.2K]

Answer:

Total tickets = 70

Total cost = $550

Adult's ticket = $9

Child's ticket = $5

Difference = 9 - 5 = $4

Assume all 70 are child's tickets

5 x 70 = 350

But the total cost was 550

550 - 350 = $200

The $200 must have come from Adult's tickets, which has a difference of $4.

200 ÷ 4 = 50

So there are 50 adult's tickets.

70 - 50 = 20

And there are 20 child's tickets.

Hope this helps - Itz.Jordan

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2 years ago