To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors.
<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>
<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>
<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
Answer:x = 9/16
Step-by-step explanation:
2x + 3 = 6x - 4
/3
First you gotta get rid of the divided by 3
2x / 3 = 2/3x and 3 / 3 = 1
Now you have
2/3x + 1 = 6x - 4
Second you have to get rid of the 2/3x on the left side
2/3x + 1 = 6x - 4
-2/3x -2/3x
1 = 5 1/3x - 4
Third you have to get rid of the -4
1 = 5 1/3x - 4
-4 -4
-3 = 5 1/3x
Fourth you have to divide by 5 1/3
-3 = 5 1/3x
/ 5 1/3 / 5 1/3
x = 9/16
