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Nataly [62]
3 years ago
14

What is the solution

Mathematics
1 answer:
ladessa [460]3 years ago
3 0

Answer:

No solutions or ∅

Step-by-step explanation:

Do the algebra:

-\frac{1}{3}+\frac{2}{3}m=\frac2 3 m - \frac 2 3 \\\\\frac 2 3 m = \frac 2 3 m - \frac 2 3\\\\0=-\frac 2 3

Since 0 ≠ -2/3, this equation has no solutions.

Hope this helped :)

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Fill in the other coordinate for the line 7x - 5y = 21: (4, )
garri49 [273]
7x - 5y = 21....(4,?)...so sub in 4 for x and solve for y
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check..
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Solve the following equation by completing the square. 3x^2-3x-5=13
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we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

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Answer:

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