Angel is x years old, in 15 years how old will Angel be?

In 2011 and 2015, the study was held to determine the proportion of people who read books. 948 people of 1200 said they read at

GuDViN [60]

Answer:

$(0.79-0.72) - 1.96 \sqrt{\frac{0.72(1-0.72)}{1200} +\frac{0.79(1-0.79)}{1500}}=0.0373$

$(0.79-0.72) + 1.96 \sqrt{\frac{0.72(1-0.72)}{1200} +\frac{0.79(1-0.79)}{1500}}=0.103$

And the 95% confidence interval would be given (0.0373;0.103).

We are confident at 95% that the difference between the two proportions is between $0.0373 \leq p_A -p_B \leq 0.103$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for A

$\hat p_A =\frac{948}{1200}=0.79$ represent the estimated proportion for A

$n_A=1200$ is the sample size required for A

$p_B$ represent the real population proportion for B

$\hat p_B =\frac{1080}{1500}=0.72$ represent the estimated proportion for B

$n_B=1500$ is the sample size required for B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.79-0.72) - 1.96 \sqrt{\frac{0.72(1-0.72)}{1200} +\frac{0.79(1-0.79)}{1500}}=0.0373$

$(0.79-0.72) + 1.96 \sqrt{\frac{0.72(1-0.72)}{1200} +\frac{0.79(1-0.79)}{1500}}=0.103$

And the 95% confidence interval would be given (0.0373;0.103).

We are confident at 95% that the difference between the two proportions is between $0.0373 \leq p_A -p_B \leq 0.103$

4 0

3 years ago

What is the output of the fuction f(x)=x+21 if the input is 4

Furkat [3]

To solve this equation, plug your input value into the function to find your output.

This would leave you with:
f(4)=4+21

Add the two integers together:
f(4)=25

So he output value of that function with he input of 4 would be 25.

5 0

3 years ago

6 less than The sum of x and y

Irina18 [472]

Answer:

(x+y)-6

This is the equation

5 0

3 years ago

Read 2 more answers

Please help 300 points

Anna71 [15]

Answer:

4x + 9 ≥ 0

Step-by-step explanation:

The inside of the square root, the radicand, cannot be negative.

It can only be zero or positive.

Zero or positive is also described as being greater than or equal to 0.

Set the radicand to be greater than or equal to zero.

4x + 9 ≥ 0

6 0

2 years ago

Read 2 more answers

A multiplication expression with a product of 108,064 is shown below. What is the missing digit? four thousand nine hundred twel

hoa [83]

Answer:

???????????

Step-by-step explanation:

sorry cant help

6 0

2 years ago