a is the correct
Explanation:
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Mass would be 104/1.16 = 89.66 kg
Weight on Earth would be 89.66 * 10 = 896.55N
Weight on Mars 89.66 * 3.7 = 331.72 N
Answer:
2.5 x 10⁻⁹ m
Explanation:
E = Energy of photon = 500 eV = 500 x 1.6 x 10⁻¹⁹ J
c = speed of photon = 3 x 10⁸ m/s
λ = wavelength of photon = ?
Energy of photon is given as
inserting the values
λ = 2.5 x 10⁻⁹ m
Answer:
<em>No, a rigid body cannot experience any acceleration when the resultant force acting on the body is zero.</em>
Explanation:
If the net force on a body is zero, then it means that all the forces acting on the body are balanced and cancel out one another. This sate of equilibrium can be static equilibrium (like that of a rigid body), or dynamic equilibrium (that of a car moving with constant velocity)
For a body under this type of equilibrium,
ΣF = 0 ...1
where ΣF is the resultant force (total effective force due to all the forces acting on the body)
For a body to accelerate, there must be a force acting on it. The acceleration of a body is proportional to the force applied, for a constant mass of the body. The relationship between the net force and mass is given as
ΣF = ma ...2
where m is the mass of the body
a is the acceleration of the body
Substituting equation 2 into equation 1, we have
0 = ma
therefore,
a = 0
this means that<em> if the resultant force acting on a rigid body is zero, then there won't be any force available to produce acceleration on the body.</em>
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Given Information:
Force = f = 1 pound
Stretched length = x = 0.1 ft
Required Information:
Work done = W = ?
Answer:
Work done = 6.05 ft.lb
Explanation:
From the Hook's law we know that
f(x) = kx
Where f is the applied force, k is spring constant and x is length of spring being stretched.
k = F/x
k = 1/0.1
k = 10 lb/ft
f(x) = 10x
The work done is given by
W = ∫ f(x) dx
Where f(x) = 10x and limits of integration are (1.1, 0)
W = ∫ 10x dx
W = 10*x²/2
W = 5x²
Evaluating the limits,
W = 5(1.1)² - 5(0)²
W = 6.05 - 0
W = 6.05 ft.lb
Therefore, 6.05 ft.lb work has been done in stretching the spring from its natural length to 1.1 feet beyond it's natural length.