Ask question

Ask question

All categories

3 years ago

12

Nancy is planning a birthday party for her co-worker,sarH. she realzes that there are 10 women and 8 men attending the office pa

rty.nancy
decides to serve pizza to the men and sandwiches to the women.complete the table

1 answer:

Zolol [24]3 years ago

6 0

The table in the attached figure

complete the table

Part 1) Gender
we have
a) Men------> Male
b)]Women----> Female

Part 2) Food
we have
a) Male------> pizza
b)]Female----> <span>sandwiches

Part 3) Headcount
</span>we have
a) Male------> pizza-----> 8
b)]Female----> sandwiches-----> 10

see the complete table in the attached figure N 2

You might be interested in

1.5/4x+1=0.4/x+4 PLEASE HELP ITS PROPORTIONS

Serhud [2]

Answer:

Proportion states that the two fractions or ratios are equal

Given the equation: $\frac{1.5}{4x+1} = \frac{0.4}{x+4}$

By cross multiply we get;

$1.5(x+4) = 0.4(4x+1)$

Using distributive property; $a\cdot (b+c) = a\cdot b+ a\cdot c$

$1.5x + 6= 1.6x + 0.4$

Subtract 0.4 from both sides we get;

$1.5x +5.6= 1.6x$

Subtract 1.5x from both sides we get;

$5.6= 0.1x$

Divide both sides by 0.1 we get;

$x = \frac{5.6}{0.1}$

Simplify:

x = 56

Therefore, the value of x that satisfy the equation $\frac{1.5}{4x+1} = \frac{0.4}{x+4}$ is, 56

5 0

3 years ago

X=4y-5<br> 2x+3y=23<br> Solve using the substitution method

jenyasd209 [6]

Answer:

x =7, y = 3

Step-by-step explanation:

We substitute the value of x in terms of y (given) into the equation.

Then we solve for y and plug in the value of y back into the equation for the value of x to find x.

3 0

3 years ago

I can’t figure out the solution I think it is y < -10

Olenka [21]

Hey there!

<em>With negatives ( $-$ ) you have to switch your symbol to the other way</em>
$\bold{\frac{y}{-2}\leq5}$
Firstly, substitute the $\bold{y\ value }$ as an invisible 1
So, now we have to flip the equation around
$\bold{\frac{-1}{2}y\leq5}$
We have to $\bold{multiply}$ by $\bold{-2}$ on each of your sides
$\bold{-2\times\frac{-1}{2}\leq-2\times5}$
$\bold{Cancel \ out:2\times\frac{-1}{2}y \ because \ it \ equal \ 1}$
$\bold{Keep: -2\times5 \ because \ it \ helps \ us \ find \ our \ answer}$
$\bold{-2\times5=-10}$
$\boxed{\boxed{\bold{Answer:y\geq-10}}}\checkmark$

Good luck on your assignment and enjoy your day!

~ $\frak{LoveYourselfFirst:)}$

<em />

4 0

3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

PLS HELP. 16points. Please number your responses to the questions as they are shown (1 and 2).

anastassius [24]

I recommend using photomath

5 0

3 years ago