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RSB [31]
2 years ago
11

Properties of rectangles rhombuses and squares worksheet answers.

Mathematics
1 answer:
Mazyrski [523]2 years ago
7 0

Answer:

sorry i cant find anything for u

Step-by-step explanation:

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A pet store currently has a total of 45 cats and dogs. There are 7 more cats than dogs. Find the number of cats and dogs in the
Evgesh-ka [11]
The dog is 19, cat is 26
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3 years ago
Choose the equation you would use to find the altitude of the airplane. tan70 = 0 tan70 = sin70 =
KonstantinChe [14]
The situation is represented by a drawing with a right triangle where an airplane is at the top corner, the elevation angle (opposite to the airplane) is 70°, the height (vertical leg) is x, and the adjacent leg (horizontal leg) to the 70° angle is 800.

Then, to find the height x, which is the opposite leg to the angle,  you can use the tangent ratio, which is opposite leg divided by adjacent leg:

tan(x) = opposite leg / adjacent leg => tan(70°) = x / 800

Answer: tan(70°) = x / 800
7 0
2 years ago
5/3÷7=_____<br>Answer in a fraction form<br><br>PLZ HELP ​
vfiekz [6]

Answer:

5/21

Step-by-step explanation:

5/3/7=?

so 5/3 *1/7=5/21

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8 0
3 years ago
Write as 0.00147 an ordinary number
cestrela7 [59]

Answer: it can be written as 1.47x10-^3

Step-by-step explanation:

3 0
2 years ago
Match the following items.
max2010maxim [7]

Answer:

1. ∠ABD = 20°.

2.  Arc AB =  140°.

3.  Arc AD =  40°.

Step-by-step explanation:

Given information: ∠ADB = 70°. BD is diameter.

According to Central angle theorem, the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points.

By Central angle theorem,

\angle DAB=90^{\circ}

Using angle sum of property in triangle ADB we get,

\angle ADB+\angle DAB+\angle  ABD=180^{\circ}

70^{\circ}+90^{\circ}+\angle  ABD=180^{\circ}

\angle  ABD=20^{\circ}.

Draw a line segment AO.

In triangle AOD, AO=OD, so

\angle ODB=\angle OAD=70^{\circ}

Using angle sum property in triangle AOD,

\angle AOD+\angle ODA+\angle  OAD=180^{\circ}

\angle AOD+70^{\circ}+70^{\circ}=180^{\circ}

\angle AOD=40^{\circ}

Therefore length of arc AD is 40°.

The angle AOD and AOB are supplementary angles.

\angle AOD+\angle AOB=180^{\circ}

40^{\circ}+\angle AOB=180^{\circ}

\angle AOB=140^{\circ}

Therefore length of arc AB is 140°.

3 0
3 years ago
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