This is how you do it: (in the picture)
Properties of rectangles rhombuses and squares worksheet answers.
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Volume =
find partial derivatives using product rule
i.e.
Using maximum for partial derivatives, we equate first partial derivative to 0.
y=0 or x+y =6
x=0 or x+4y =12
Simplify to get y =2, x = 4
thus critical points are (4,2) (6,0) (0,3)
Of these D the II derivative test gives
D<0 only for (4,2)
Hence maximum volume is when x=4, y=2, z= 4/3
Max volume is = 4(2)(4/3) = 32/3