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dezoksy [38]
4 years ago
6

Can someone please have a heart to help me this is for a grade

Mathematics
2 answers:
nordsb [41]4 years ago
5 0

Hey there!

Let's start by solving for x.

Take the first equation, y = -3x - 7, and substitute in the second equation, y = x + 9, for y.

We now have:

x + 9 = -3x - 7

Add 3x to both sides.

4x + 9 = -7

Subtract 9 from both sides.

4x = -16

Divide each side by 4.

x = -4

Let's use the second equation, y = x + 9, to solve for x.

Put in the value we just solved for.

We now have:

y = -4 + 9

Simplify.

y = 5

Let's check our answer, starting with the first equation, y = -3x - 7.

Put in the values for x and y.

5 = -3(-4) - 7

5 = 12 - 7

5 = 5

Do the same with the second equation, y = x + 9.

5 = -4 + 9

5 = 5

The solution to the system of equations is (5, -4).

Hope this helps!

Kitty [74]4 years ago
3 0

Answer:

(-4, 5)

Step-by-step explanation:

Since y = -3x - 7 in the first equation, substitute y of the second equation with -3x - 7:

-3x - 7 = x + 9

Subtract x from both sides. Add 7 to both sides.

-4x = 16

Divide both sides by -4.

x = -4

Now, substitute -4 for x in the second equation.

y = -4 + 9

y = 5

The solution is:

x = -4; y = 5

As an ordered pair, the solution is:

(-4, 5)

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4 years ago
1) solve for w: 3w - 10 = 4w + 5<br> 2) solve for t:6 -2t &gt;18
Gre4nikov [31]
Problem # 1
 3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)

problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12 
(-1) (-2t) >  12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
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5 0
4 years ago
What is the axis of symmetry of h(x) = –2x2 + 12x – 3?
murzikaleks [220]
The axis of symmetry is the x value of the vertex
we have a handy-dandy way of finding that from standard form, ax^2+bx+c=y

for
ax^2+bx+c=y
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4 years ago
Read 2 more answers
Please please help me
Soloha48 [4]
The answer is D, they are independent because they intersect at one point.
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